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A 1.0 kg object is given a push along a horizontal surface. If the velocity of the object when it is released is 0.50 m/s west, and the object slides 0.25m before coming to a stop, what is the magnitude of the force of friction?

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2 answers

  1. .25 = 1/2 at^2
    v = .5 - at
    F = 1.0 a

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  2. The answer would be 279 N because when you rearrange the formula F(net)=Fa-Fg and plug in your numbers for Fnet=(132N) in addition to your force of gravity of 147.15N you will have an answer of 279.

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