What are the concentrations of OH– and H in a 0.00070 M solution of Ba(OH)2 at 25 °C? Assume complete dissociation.
conc OH=2*.00070
concH=1E-14/concOH
Oh, the concentrations of OH⁻ and H⁺ in a Ba(OH)2 solution? Well, let me calculate that for you with a little chemistry and a touch of humor!
Ba(OH)2 is a strong base that fully dissociates in water, leaving behind Ba²⁺ ions and two OH⁻ ions. So, for every mole of Ba(OH)2, we have two moles of OH⁻. Since you have a 0.00070 M solution of Ba(OH)2, it means you have twice that concentration of OH⁻. So, the concentration of OH⁻ is 0.00140 M.
Now, as for H⁺ concentration, let me tell you a funny twist! Ba(OH)2 doesn't directly produce any H⁺ ions. It's like giving me a fishing rod and expecting me to find a unicorn in the sea! So, in this case, the concentration of H⁺ is essentially zero.
Remember, laughter is always the best solution, even in chemistry!
To find the concentrations of OH- and H+ in a 0.00070 M solution of Ba(OH)2 at 25 °C, we need to consider the complete dissociation of Ba(OH)2.
Ba(OH)2 dissociates completely into Ba2+ and 2 OH- ions.
Therefore, the concentration of OH- ions in the solution is twice the concentration of Ba(OH)2.
Concentration of OH- ions = 2 * 0.00070 M = 0.00140 M.
In pure water, the concentration of H+ ions (or H3O+) is 10^(-7) M.
Since Ba(OH)2 dissociates completely, the solution will be highly basic, and the concentration of H+ ions will be negligible.
Thus, the concentration of H+ ions in the solution is very close to zero.
To find the concentrations of OH- and H+ ions in a solution of Ba(OH)2, we need to consider the dissociation of Ba(OH)2.
Ba(OH)2 is a strong base and completely dissociates in water to give Ba2+ ions and OH- ions. Since Ba(OH)2 dissociates completely, the concentration of Ba2+ ions is twice the concentration of Ba(OH)2.
Given that the concentration of Ba(OH)2 is 0.00070 M, the concentration of Ba2+ ions would be (0.00070 M) × 2 = 0.00140 M.
Since there are two OH- ions produced for every Ba(OH)2 molecule that dissociates, the concentration of OH- ions is also twice the concentration of Ba(OH)2.
Therefore, the concentration of OH- ions in the solution is (0.00070 M) × 2 = 0.00140 M.
Since OH- ions are produced in the dissociation process, the concentration of H+ ions can be considered negligible. Hence, we can assume that the concentration of H+ ions is approximately 0 M in this solution.
Therefore, the concentrations of OH- and H+ ions in the 0.00070 M Ba(OH)2 solution at 25 °C are 0.00140 M and approximately 0 M, respectively.