A car starts from rest and accelerates unifomly at 3m/s^2. A second car starts from rest 6 seconds later at the same point and accelerates uniformly at 5m/s^2. How long does it take the second car to over take the first car?
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1 answer

Solve this equation for t:
(3/2) t^2 = (5/2)(t6)^2
You should get an equation of the form
at^2 + bt + c = 0.
Take the root that is t>6 👍
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