A dragster and a driver together have mass of 942.2 kg. the dragster starting from rest attains a speed of 25.5m/s in 0.56 s.
1. find the average acceleration of the dragster during this time interval? I really need the formula
2. What horizontal force does the seat exert on the driver? i have the weight of the driver again i need the formula please
1. The formula to calculate average acceleration is:
Average acceleration = (final velocity - initial velocity) / time
In this case, the final velocity is 25.5 m/s, the initial velocity is 0 m/s (starting from rest), and the time is 0.56 seconds. Plugging these values into the formula:
Average acceleration = (25.5 m/s - 0 m/s) / 0.56 s
2. To calculate the horizontal force exerted by the seat on the driver, we need to consider the net external force acting on the driver-dragster system. Since the seat exerts the only horizontal force, it must be equal to the net external force. This net external force can be found using Newton's second law:
Net external force = mass of the system * acceleration
In this case, the mass of the system is 942.2 kg (given), and the acceleration can be found from the previous calculation. Plugging these values into the formula:
Net external force = 942.2 kg * (acceleration calculated in question 1)
1. To find the average acceleration of the dragster, you can use the formula:
Average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 m/s (starting from rest)
Final velocity (v) = 25.5 m/s
Time (t) = 0.56 s
Plugging in the values, the formula becomes:
Average acceleration = (25.5 m/s - 0 m/s) / 0.56 s
Simplifying it further:
Average acceleration = 25.5 m/s / 0.56 s
Average acceleration ≈ 45.5357 m/s²
Therefore, the average acceleration of the dragster during this time interval is approximately 45.54 m/s².
2. To find the horizontal force exerted by the seat on the driver, you need to consider the net force acting on the driver.
The net force is given by Newton's second law of motion:
Net force = mass × acceleration
Given:
Mass (m) = mass of the dragster + mass of the driver = 942.2 kg
Acceleration (a) = average acceleration calculated in step 1 ≈ 45.54 m/s²
Now, we can plug in these values into the formula:
Net force = 942.2 kg × 45.54 m/s²
Net force ≈ 42923.188 kg·m/s²
However, we can relate force and weight since weight is the force exerted by gravity on an object. The weight of an object is given by:
Weight = mass × acceleration due to gravity
Let's assume the acceleration due to gravity (g) is 9.8 m/s² (standard value on Earth). Since the vertical force (weight) does not contribute to the horizontal force, we can ignore it. Therefore, the horizontal force exerted by the seat on the driver can be approximated to the net force itself.
Therefore, the horizontal force exerted by the seat on the driver is approximately 42923.188 N.
1. To find the average acceleration of the dragster during the time interval, you can use the formula:
Average acceleration = (Final velocity - Initial velocity) / Time
In this case, the initial velocity is 0 m/s (starting from rest), the final velocity is 25.5 m/s, and the time is given as 0.56 s.
Using the formula, the average acceleration can be calculated as:
Average acceleration = (25.5 m/s - 0 m/s) / 0.56 s
2. To find the horizontal force exerted by the seat on the driver, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object times its acceleration:
Net Force = Mass × Acceleration
In this case, the mass of both the dragster and the driver together is given as 942.2 kg, and the acceleration can be considered as the average acceleration calculated in the previous step.
Using Newton's second law, the horizontal force exerted by the seat on the driver can be calculated as:
Force = Mass × Acceleration
To clarify, the weight of the driver is not required to calculate the horizontal force exerted by the seat.
1. acceleration is speed change divided by time. In this case it is
a = 25.5/0.56 m/s^2
2. F = m a
where m is the driver's mass (not weight)
The answer, if you do it right, will be in newtons.