A scientist wants to make a solution of tribasic sodium phosphate, , for a laboratory experiment. How many grams of will be needed to produce 625 of a solution that has a concentration of ions of 0.800
You want how many moles of Na^+? That is M x L = 0.800M x 0.625L =??
Convert that to moles Na3PO4 remmbering that there are 3 atoms Na per 1 molecule Na3PO4; therefore,
?moles Na^+ x (1 mole Na3PO4/3 moles Na^+) = moles Na3PO4.
moles Na3PO4 = grams Na3PO4 x molar mass Na3PO4.
32.5
How many grams of Na3PO4 will be needed to produce 625mLof a solution that has a concentration of Na+ ions of 1.50M?
To determine the number of grams of tribasic sodium phosphate (Na3PO4) needed to produce a solution with a specific concentration, we need to use the formula:
Concentration (mol/L) = Number of moles / Volume of solution (L)
First, we need to find the number of moles of Na3PO4 required to achieve a concentration of 0.800 mol/L. To do this, we rearrange the formula:
Number of moles = Concentration × Volume of solution (L)
Given that the concentration is 0.800 mol/L and the volume of the solution is 625 mL (or 0.625 L), we can plug these values into the formula:
Number of moles = 0.800 mol/L × 0.625 L
Now, we have the number of moles of Na3PO4 required to make the solution. To convert moles to grams, we need the molar mass of Na3PO4. The molar mass of Na3PO4 can be calculated by adding up the atomic masses of its components.
The atomic mass of sodium (Na) is 22.99 g/mol, and there are three sodium atoms in Na3PO4:
3 × 22.99 g/mol = 68.97 g/mol
The atomic mass of phosphorus (P) is 30.97 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol, and there are four oxygen atoms in Na3PO4:
4 × 16.00 g/mol = 64.00 g/mol
Now, we can calculate the molar mass of Na3PO4 by adding up the atomic masses:
molar mass of Na3PO4 = 68.97 g/mol + 30.97 g/mol + 64.00 g/mol = 163.94 g/mol
Finally, we can calculate the number of grams of Na3PO4 needed by multiplying the number of moles obtained earlier by the molar mass:
Number of grams = Number of moles × Molar mass
Number of grams = (0.800 mol/L × 0.625 L) × 163.94 g/mol
So, to produce a 625 mL solution with a concentration of 0.800 mol/L of ions, you will need approximately *rounding to the nearest whole gram*:
Number of grams ≈ (0.800 mol/L × 0.625 L) × 163.94 g/mol
Please note that the exact value will depend on the number of significant figures used throughout the calculation.