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The force required to stretch a Hooke’s-law

spring varies from 0 N to 62.4 N as we stretch
the spring by moving one end 17.2 cm from
its unstressed position.
a) Find the force constant of the spring.
Answer in units of N/m

b) Find the work done in stretching the spring.
Answer in units of J

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2 answers
  1. a) 62.4 N/0.172 m = 362.8 N/m

    b) (1/2)*(max stretch)(max force)
    = 0.5*0.172 m*62.4 N = ___ J

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  2. thank you for the help!!!

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