You have a solution that contains 5.0 grams of oxalic acid dissolved in 150 mL of water. This solution is placed in a separatory funnel, and the 100 mL of diethyl ether is added to the separatory funnel and an extraction is performed. Use the following constants to calculate how much oxalic acid is in solvent after the extraction.

Solubility of oxalic acid in water= 9.5 g/100 mL
Solubility of oxalic acid in ether= 16.9 g/100 mL

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To calculate how much oxalic acid is in the solvent after the extraction, we need to consider the solubility of oxalic acid in water and ether, as well as the initial amount of oxalic acid in the solution.

1. Calculate the amount of oxalic acid that can dissolve in water:
Solubility of oxalic acid in water = 9.5 g/100 mL
Amount of water used = 150 mL

Therefore, the maximum amount of oxalic acid that can dissolve in 150 mL of water is:
(9.5 g/100 mL) x (150 mL) = 14.25 grams

2. Calculate the amount of oxalic acid that can dissolve in ether:
Solubility of oxalic acid in ether = 16.9 g/100 mL
Amount of ether used = 100 mL

Therefore, the maximum amount of oxalic acid that can dissolve in 100 mL of ether is:
(16.9 g/100 mL) x (100 mL) = 16.9 grams

3. Determine the initial amount of oxalic acid in the solution:
Initial amount of oxalic acid in the solution = 5.0 grams

4. Calculate the remaining amount of oxalic acid in the solvent after the extraction:
Remaining amount of oxalic acid in the solvent = Initial amount - Amount dissolved in water + Amount dissolved in ether.

Remaining amount = 5.0 g - 14.25 g + 16.9 g
Remaining amount = 7.65 grams

Therefore, after the extraction, there are approximately 7.65 grams of oxalic acid in the solvent.

To calculate how much oxalic acid is in the solvent after the extraction, we need to determine the amount of oxalic acid that remains in the water and the amount that transfers to the ether.

1. Calculate the amount of oxalic acid in the original solution:
OXAcid_water = solubility_water * volume_water
OXAcid_water = (9.5 g/100 mL) * 150 mL
OXAcid_water = 14.25 g

2. Calculate the amount of oxalic acid that transfers to the ether:
OXAcid_ether = solubility_ether * volume_ether
OXAcid_ether = (16.9 g/100 mL) * 100 mL
OXAcid_ether = 16.9 g

3. Subtract the amount of oxalic acid in the ether from the total amount in the original solution to find the remaining amount in the water:
OXAcid_remaining = OXAcid_water - OXAcid_ether
OXAcid_remaining = 14.25 g - 16.9 g
OXAcid_remaining = -2.65 g

The negative result indicates that more oxalic acid transfers to the ether phase than remains in the water phase after the extraction.

Therefore, after the extraction, there is no oxalic acid left in the water phase, and there is a net transfer of 2.65 g of oxalic acid to the ether phase.

Ko/aq = 16.9/9.5 = ?

How much is in WHICH solvent after the extraction.
Let x = oxalic acid in water
then 5.0-x = oxalic acid in ether.

K = [(5.0-x)/100]/(x/150)
Solve for x.