You have a solution that contains 5.0 grams of oxalic acid dissolved in 150 mL of water. This solution is placed in a seqparatory funnel, and the 100 mL of diethyl ether is added to the separatory funnel and an extraction is performed. Use the following constants to calculate how much oxalic acid is in solvent after the extraction.

Solubility of oxalic acid in water= 9.5 g/100 mL
Solubility of oxalic acid in ether= 16.9 g/100 mL

Well, well, look at you, playing around with solubility and extraction. You're really stirring things up! Now, let's see what we can do with this.

First, let's calculate how much oxalic acid is initially dissolved in the water. We have 5.0 grams dissolved in 150 mL of water. Using simple math, we can determine that the concentration is 5.0 g / 150 mL = 0.033 g/mL.

Now, let's move on to the extraction. We're adding 100 mL of diethyl ether, which has a solubility of oxalic acid of 16.9 g/100 mL. If we do the math, we find that we should be able to extract 16.9 g from this amount of ether.

But here's the catch: oxalic acid is a sneaky little compound. It likes water so much that it just can't resist staying in it. So, after the extraction, we can assume that all the oxalic acid will remain in the water. That means, the amount of oxalic acid in the solvent after the extraction is... you guessed it, zero!

So, my dear chemist, after this extraction, you'll have a funnel with some pure diethyl ether and an oxalic acid-free water layer. Keep up the good work, and remember to always have fun with chemistry!

To calculate how much oxalic acid is in the solvent after the extraction, we first need to determine how much oxalic acid remains in the water and how much is transferred to the ether during the extraction process.

Given:
Mass of oxalic acid in the original solution = 5.0 grams
Volume of water used = 150 mL
Volume of ether used = 100 mL
Solubility of oxalic acid in water = 9.5 g/100 mL
Solubility of oxalic acid in ether = 16.9 g/100 mL

Step 1: Calculate the amount of oxalic acid dissolved in the water before the extraction.
Using the solubility of oxalic acid in water, we can calculate the maximum amount of oxalic acid that can dissolve in 150 mL of water:
Solubility of oxalic acid in water = 9.5 g/100 mL
Therefore, the maximum amount of oxalic acid that can dissolve in 150 mL of water is:
(9.5 g/100 mL) x (150 mL) = 14.25 grams

Step 2: Calculate the remaining amount of oxalic acid in the water after the extraction.
Since the solubility of oxalic acid in water is given as 9.5 g/100 mL, we can assume that after the extraction, the water will still contain the same concentration of oxalic acid.
To find the remaining amount of oxalic acid in the water, we can use the following proportion:
(14.25 g) / (5.0 g) = (x g) / (150 mL)

Solving for x, we get:
x = (14.25 g) x (150 mL) / (5.0 g)
x = 42.75 g

Therefore, after the extraction, there will be 42.75 grams of oxalic acid left in the water.

Step 3: Calculate the amount of oxalic acid transferred to the ether.
The initial amount of oxalic acid in the solution is 5.0 grams. From the above calculation, we determined that 42.75 grams remained in the water. Therefore, the amount of oxalic acid transferred to the ether can be obtained by subtracting the remaining amount from the initial amount:
Amount of oxalic acid transferred to ether = 5.0 g - 42.75 g = -37.75 g

Notice that the negative sign indicates that no oxalic acid was transferred from the water to the ether. This implies that the solubility of oxalic acid in water is less than the solubility of oxalic acid in ether.

Therefore, after the extraction, there is no oxalic acid in the ether since no transfer occurred.