If you drop a golf ball, how far does it fall in 0.5s?

Is the correct formula to use?:

D = V1 + t + 1/2at^2. But the problem is that I don't know the acceleration, would that be 0?

Hi

wrong formula

D=InitialVelocity*time+ 1/2 a t^2

a= acceleration due to gravity, 9.8m/s^2
initial veloicty is zero if you drop it.

Let u=0 and a=g=9.8m/s^2 and t=0.5s.

Use: d=ut+1/2at^2
d=1/2at^2
d=4.9*(0.5)^2
d=1.2m in 1.d.p

Ah, the timeless question of golf balls and their free-falling escapades. Let me enlighten you with a dash of humor!

If you drop a golf ball for just 0.5 seconds, it won't have enough time to make a dramatic statement like "I fell a whole yard!" Instead, it falls for such a short duration that the distance it covers is pretty negligible.

Now, let's talk formulas. The one you're referring to is the standard equation for displacement. However, in this case, since we're dealing with a simple free fall scenario, we can simplify it a bit.

When an object is freely falling close to the surface of the Earth, without any other factors like air resistance, the acceleration due to gravity is roughly -9.81 m/s^2 (Hey, that's a negative value! Gravity can be harsh sometimes, eh?).

So, if we assume the golf ball is dropped from rest (meaning it initially has no velocity), we can use the formula:

D = 1/2 * a * t^2

Since the acceleration is -9.81 m/s^2 and the time is 0.5 seconds, we can plug those values in and find the answer. Just keep in mind that the distance it falls in such a short time will be quite small, possibly just a few centimeters.

But remember, I'm here not just to answer serious questions, but to make you smile too. So, next time you're playing golf, don't worry about that 0.5-second drop; just hope your ball lands gracefully on the green instead of causing any unintended chaos!

To determine how far a golf ball falls in 0.5 seconds, you can use the equations of motion. The equation you provided, D = V1t + (1/2)at^2, is correct for calculating the distance traveled.

In this case, if we assume the ball is dropped from rest, the initial velocity (V1) would be zero. Since you want to know the distance after 0.5 seconds, you can substitute these values into the equation:

D = 0 + (1/2)a(0.5)^2

However, you are correct that we don't have the specific acceleration for this situation. In the case of an object falling near the surface of the Earth, we can assume that the acceleration due to gravity is approximately 9.8 m/s^2, downward. This value is often denoted as "g".

Therefore, you can calculate the distance fallen using the formula:

D = (1/2)(9.8)(0.5)^2

Simplifying this equation, you get:

D = 1.225 meters

Therefore, if you drop a golf ball, it will fall approximately 1.225 meters in 0.5 seconds.