the perimeter of a rectangle is 56 inches> the width of the rectangle is three-fourth of the length. Find the length of the diagonal of the rectangle.
please help me!!!
What are the examples for the six parent functions?
the perimeter of a rectangle is 56 inches the width of the rectangle is three-fourth of the length. Find the length of the diagonal of the rectangle.
please help me!!!
multiplying a number by x yields the same result as divinding the number by .125. what is tge vaule of it.
LET LENGTH'l' be x
breadth 'b'=3x/4
perimetre=2(l+b)
56=2(x+3x/4)
28=7x/4
x=16
l=16,b=12
from pythogaras theorem
d2=b2+h2
d2=256+144
d2=400
d=20 (square root of 400=20)
the length of a rectangle is 100 inches more than the width. if the perimeter of the rectangle is 1320 inches find the demensions
Why did the rectangle go to the doctor?
Because it wasn't feeling quite square!
Now, let's solve this math problem together.
Let's assume the length of the rectangle is "x" inches.
According to the problem, the width is three-fourths of the length, so the width would be (3/4)x inches.
The formula for the perimeter of a rectangle is P = 2(length + width).
Given that the perimeter is 56 inches, we can now set up the equation:
56 = 2(x + (3/4)x)
Let's simplify the equation:
56 = 2(7/4)x
Now, divide both sides by 2 to solve for x:
28 = (7/4)x
Multiply both sides by 4/7:
x = (4/7) * 28
Simplifying further:
x = 16
So, the length of the rectangle is 16 inches.
To find the diagonal, we can use the Pythagorean theorem.
The diagonal, d, can be found using the equation d^2 = length^2 + width^2.
d^2 = 16^2 + (3/4*16)^2
d^2 = 256 + (12)^2
d^2 = 256 + 144
d^2 = 400
d = √400
d = 20
So, the length of the diagonal of the rectangle is 20 inches.
To find the length of the diagonal of the rectangle, we need to first find the length and width of the rectangle.
Let's assume the length of the rectangle is 'L' inches. According to the problem, the width of the rectangle is three-fourths of the length. So, the width can be expressed as (3/4)L.
The perimeter of a rectangle is given by the formula: 2(length + width). According to the problem, the perimeter is 56 inches. So, we can write the equation as:
2(L + (3/4)L) = 56
Now, we can solve this equation to find the value of L.
2 (L + (3/4)L) = 56
2 (7/4L) = 56
(7/4L) = 56 / 2
(7/4L) = 28
7L = 4 * 28
7L = 112
L = 112 / 7
L = 16
Therefore, the length of the rectangle is 16 inches.
Now, we can find the width of the rectangle by substituting the value of L in the equation (3/4)L.
Width = (3/4) * 16
Width = 12 inches
To find the length of the diagonal, we can use Pythagoras' theorem, which states that in a right-angled triangle, the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides.
In this case, the diagonal is the hypotenuse, and the length and width are the other two sides of the right-angled triangle.
The length and width form a right angle, so we can create a right-angled triangle. The diagonal will be the hypotenuse, and the length and width will be the other two sides.
Using Pythagoras' theorem, we can write the equation:
Diagonal^2 = Length^2 + Width^2
Substituting the values, we get:
Diagonal^2 = 16^2 + 12^2
Diagonal^2 = 256 + 144
Diagonal^2 = 400
To find the value of the diagonal, we take the square root of both sides:
Diagonal = √400
Diagonal = 20 inches
Therefore, the length of the diagonal of the rectangle is 20 inches.