The air exerts a forward force of 10 N on the propeller of a 0.20 kg model airplane. If the plane accelerates forward at 5.0 m/s2, what is the magnitude of the resistive force exerted by the air on the airplane in Newtons ?
Fnet = Fprop - Friction = m*a
Solve for the resistive force, which I have called Ffriction
Fprop is the forward thrust of the propeller.
You know what m and a are.
10N
To find the magnitude of the resistive force exerted by the air on the airplane, we need to consider Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Force exerted by air on the propeller = 10 N
Mass of the airplane = 0.20 kg
Acceleration of the airplane = 5.0 m/s^2
Using Newton's second law, we can rearrange the formula to solve for the net force:
Net force = Mass × Acceleration
Net force = 0.20 kg × 5.0 m/s^2
Net force = 1.0 N
Since the force exerted by the air on the propeller is in the forward direction, and the plane is accelerating in the forward direction, the resistive force exerted by the air on the plane must be in the opposite direction (opposite to the motion of the plane).
Therefore, the magnitude of the resistive force exerted by the air on the airplane is 1.0 N (in the opposite direction).
To find the magnitude of the resistive force exerted by the air on the airplane, you need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the force exerted by the air on the propeller is the same as the force exerted by the propeller on the air - according to Newton's third law of motion, they are equal in magnitude but opposite in direction.
Given:
Mass of the model airplane (m) = 0.20 kg
Acceleration of the airplane (a) = 5.0 m/s^2
Using Newton's second law of motion:
Force (F) = mass (m) x acceleration (a)
F = 0.20 kg x 5.0 m/s^2
F = 1.0 N
The magnitude of the resistive force exerted by the air on the airplane is 1.0 Newtons.