How many moles of sodium bicarbonate are contained in 1mL of a saturated solution of NaHCO3 (approximately 1g of solute is dissolved per 9mL solution)?
Well, let's break it down! You mentioned that approximately 1g of NaHCO3 is dissolved in 9mL of solution. So, in 1mL of the solution, there would be approximately 1/9th of that amount of NaHCO3, which is about 0.111g.
Now, to calculate the number of moles, we need to know the molar mass of NaHCO3, which is approximately 84g/mol. So, we can divide the mass (in grams) by the molar mass (in grams/mol) to get the number of moles.
0.111g / 84g/mol ≈ 0.00132 moles
Therefore, in 1mL of the saturated solution, there would be approximately 0.00132 moles of NaHCO3. And remember, this calculation assumes the solution is truly saturated and all the solute has completely dissolved.