# 2H2(g)+ O2(g) --> 2H2O(L)

I know the oxidizing agent is oxygen and the reducing agent is hydrogen.

what are the number of electrons transferred in the balanced chemical equation? (I put 2 and tried -2 but it didn't seem right)

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1. H on the left is zero and it goes to +4 (all of them that is) so the loss of electrons is 4
Oxygen is zero on the left and -4 on the right (for the two of them). Therefore, the gain of electrons is 4.

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2. thanks

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3. I am lost on how to write the half reactions for the oxidation and reduction parts.Thank you

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