A student estimated the volume of liquid in a beaker as 200 mL. When she poured the liquid into a graduated cylinder, she measured the volume as 216 mL. What is the percent error of the estimated volume from the beaker, taking the measurement in the graduated cylinder as the accepted value?
would the answer be 1.85 or 1.81
(220-216)/(220) or (220-216)/(216)
This question is right OMG
its 4%
To calculate the percent error, you need to use the formula:
Percent Error = |(Measured Value - Accepted Value)| / Accepted Value * 100
In this case, the measured value is 216 mL (from the graduated cylinder) and the accepted value is 200 mL (the estimated volume in the beaker). Plugging in these values, the calculation becomes:
Percent Error = |(216 - 200)| / 200 * 100
Percent Error = 16 / 200 * 100
Percent Error = 8%
Therefore, the correct answer is 8, neither 1.85 nor 1.81.
To calculate the percent error, you need to use the formula:
Percent Error = (|Observed Value - Accepted Value| / Accepted Value) * 100
In this case, the estimated volume in the beaker is the observed value, and the measured volume in the graduated cylinder is the accepted value. We have:
Estimated Volume = 200 mL
Measured Volume = 216 mL
Using the formula:
Percent Error = (|216 - 200| / 216) * 100
= (16 / 216) * 100
= 0.074 * 100
= 7.4
Therefore, the correct answer is 7.4, not 1.85 or 1.81.