consider the fo9rmula for Al2(SO4)3,which is used in perspirants:

a. how many moles of sulfur are present i 3.0 moles of Al2(SO4)3
b. ow many moles of aluminum ions are present in 0.40 mole of Al2(SO4)3

for a and b i multiplied by 6.02*1023 power andgot
a=18.06*1024
b=9.03 *1024

No need to count atoms/molecules.

In 3.0 moles, there are 9.0 moles of S
In .40 moles, there are .80 moles of Al ions

0.8 moles of Al ions

7.8

To find the number of moles of sulfur present in 3.0 moles of Al2(SO4)3, we need to determine the number of moles of sulfur per mole of Al2(SO4)3.

The formula for Al2(SO4)3 tells us that there are three sulfate ions (SO4) for every two aluminum ions (Al2). Each sulfate ion contains one sulfur atom.

So, to calculate the number of moles of sulfur, we'll focus on the sulfate ions within Al2(SO4)3.

1 mole of Al2(SO4)3 contains 3 moles of sulfate ions, which means that 1 mole of Al2(SO4)3 contains 3 moles of sulfur.

Therefore, if we have 3.0 moles of Al2(SO4)3, we can multiply it by the conversion factor of 3 moles of sulfur per 1 mole of Al2(SO4)3:

3.0 moles Al2(SO4)3 * (3 moles S)/(1 mole Al2(SO4)3) = 9.0 moles of sulfur

So, there are 9.0 moles of sulfur in 3.0 moles of Al2(SO4)3.

For the second question, we can use a similar approach.

If we have 0.40 moles of Al2(SO4)3, we can calculate the number of moles of aluminum ions by considering that 1 mole of Al2(SO4)3 contains 2 moles of aluminum ions.

Therefore, we can multiply 0.40 moles of Al2(SO4)3 by the conversion factor of 2 moles of Al/(1 mole Al2(SO4)3):

0.40 moles Al2(SO4)3 * (2 moles Al)/(1 mole Al2(SO4)3) = 0.80 moles of aluminum ions

So, there are 0.80 moles of aluminum ions in 0.40 moles of Al2(SO4)3.

Note: The values you provided by multiplying by 6.02*10^23 are the number of atoms, not moles.