HCN is mixed with water. Which is the best

description of what you would expect to find
in the solution?
1. CN−, OH−, and water molecules
2. HCN molecules, H3O+, CN1−, and water
molecules
3. H2CN+, OH−, and water molecules
4. H3O+, CN−, and water molecules
5. CN+, OH−, and water molecules
6. HCN molecules and water molecules

Well, well, well! Looks like we have a chemistry question here. Let me put on my lab coat and goggles! *puts on virtual lab coat and goggles*

If you mix good old HCN with water, you'll end up with a solution. And what's swirling around in that solution, you ask? Well, option number 2 seems to be like the life of the party here!

You'll have HCN molecules, making themselves comfortable in the solution. Then you'll have H3O+ (which is like the party animal of the water molecules) and CN1- mingling around as well. Of course, we can't forget about the water molecules themselves, they're just hanging out, playing the music, and ensuring everyone has a good time.

So, option number 2 is the winner, my friend! Enjoy your chemistry party! *waves virtual test tube*

The best description of what you would expect to find in the solution when HCN is mixed with water is:

2. HCN molecules, H3O+, CN1−, and water molecules

To determine the correct answer, we need to understand the chemical properties of HCN (hydrogen cyanide) and its behavior when mixed with water.

HCN is a weak acid that reacts with water to form hydrogen ions (H+) and cyanide ions (CN-). In water, HCN molecules can undergo a dissociation reaction:

HCN + H2O ⇌ H3O+ + CN-

This reaction produces hydronium ions (H3O+) and cyanide ions (CN-) in the solution.

Therefore, the correct answer is option 2: HCN molecules, H3O+, CN-, and water molecules. This option accurately describes the presence of HCN molecules, hydronium ions, cyanide ions, and water molecules in the solution.

HCN is a weak acid.

HCN + H2O <==> H3O^+ + CN^-
This equation tells you what is there. Note the arrow is a double one, the reaction in an equilibrium with some of both sides at equilibrium.