A volume of equimolar strong acid like HCl

is mixed with an equal volume of equimolar
strong base like NaOH in a beaker of water.
What exists after the reaction?

water, na+, cl-

ut

I must admit I don't know what an equimolar solution of HCl is; however, in the context of the problem I assume you are trying to say that the HCl and the KOH are the same molarity. I understand that two solutions can be equimolar but I don't know how one solution can be equimolar. At any rate, if the solutions have the same molarity and equal volumes are mixed, then moles acid exactly equal moles base, so you have neither HCl nor NaOH remaining but they have combined to produce a salt, NaCl, which completely dissociates in aqueous solution to form Na^+ and Cl^-. You also have water.

Well, after this explosive encounter of HCl and NaOH, what exists in that beaker is a party! And by party, I mean a neutral solution of water and table salt (NaCl). The HCl and NaOH have reacted to form water (H2O) and sodium chloride (NaCl). So, we can say that they have happily turned into good ol' saltwater!

When an equimolar volume of a strong acid, such as HCl, is mixed with an equal volume of a strong base, such as NaOH, in a beaker of water, a neutralization reaction takes place. The H+ ions from the acid react with the OH- ions from the base to form water (H2O).

The reaction can be represented as follows:
HCl + NaOH → NaCl + H2O

In this reaction, the sodium ions (Na+) from the base combine with the chloride ions (Cl-) from the acid to form sodium chloride (NaCl), which is a salt. The water molecules (H2O) remain in the beaker.

Thus, after the reaction, what exists in the beaker is a solution of sodium chloride (NaCl) dissolved in water.

When equimolar volumes of a strong acid, such as HCl (hydrochloric acid), and a strong base, such as NaOH (sodium hydroxide), are mixed together in water, a neutralization reaction occurs. This reaction releases water and forms a salt.

In the case of HCl and NaOH, they react according to the following balanced chemical equation:

HCl + NaOH -> NaCl + H2O

This equation illustrates that one molecule of HCl reacts with one molecule of NaOH, resulting in the formation of one molecule of NaCl (sodium chloride) and one molecule of H2O (water).

So, after the reaction, what exists in the beaker is a solution containing sodium chloride (NaCl), which is a salt, along with water. The solution will be neutral since the strong acid and strong base have reacted to form a salt, which does not have acidic or basic properties.