Write the balanced molecular, complete ionic, and net ionic equations for the reactions that occur when the following are mixed. (Type your answer using the format [NH4]+ for NH4+ and [Ni(CN)4]2- for Ni(CN)42-. Use the lowest possible coefficients.)
(a) solid silver hydroxide and hydrobromic acid
molecular equation, complete ionic equation, net ionic equation
(b) aqueous strontium hydroxide and hydroiodic acid
molecular equation, complete ionic, net ionic
(c) solid iron(III) hydroxide and nitric acid
molecular equation, net ionic, complete ionic
To write the balanced molecular, complete ionic, and net ionic equations, we need to first write the formulas of the compounds involved and then balance the equation by adjusting the coefficients to ensure that the number of atoms on the reactant side is equal to the number of atoms on the product side.
(a) Solid silver hydroxide and hydrobromic acid:
The formula for silver hydroxide is AgOH, and the formula for hydrobromic acid is HBr.
Molecular equation: AgOH + HBr -> AgBr + H2O
Complete ionic equation: Ag+(aq) + OH-(aq) + H+(aq) + Br-(aq) -> AgBr(s) + H2O(l)
To get the net ionic equation, we need to eliminate the spectator ions (ions that appear on both sides of the equation without undergoing any change). In this case, the spectator ions are Ag+ and Br-.
Net ionic equation: OH-(aq) + H+(aq) -> H2O(l)
(b) Aqueous strontium hydroxide and hydroiodic acid:
The formula for strontium hydroxide is Sr(OH)2, and the formula for hydroiodic acid is HI.
Molecular equation: Sr(OH)2 + 2HI -> SrI2 + 2H2O
Complete ionic equation: Sr2+(aq) + 2OH-(aq) + 2H+(aq) + 2I-(aq) -> SrI2(s) + 2H2O(l)
To get the net ionic equation, we need to eliminate the spectator ions (Sr2+ and 2I-).
Net ionic equation: 2OH-(aq) + 2H+(aq) -> 2H2O(l)
(c) Solid iron(III) hydroxide and nitric acid:
The formula for iron(III) hydroxide is Fe(OH)3, and the formula for nitric acid is HNO3.
Molecular equation: Fe(OH)3 + 3HNO3 -> Fe(NO3)3 + 3H2O
Complete ionic equation: Fe3+(aq) + 3OH-(aq) + 3H+(aq) + 3NO3-(aq) -> Fe(NO3)3(s) + 3H2O(l)
To get the net ionic equation, we need to eliminate the spectator ions (Fe3+ and 3NO3-).
Net ionic equation: 3OH-(aq) + 3H+(aq) -> 3H2O(l)
Remember, when writing net ionic equations, only include the species that undergo a chemical change and exclude the spectator ions.
(a) The balanced molecular equation for the reaction between solid silver hydroxide (AgOH) and hydrobromic acid (HBr) is:
AgOH + HBr → AgBr + H2O
The balanced complete ionic equation is:
Ag+(aq) + OH-(aq) + H+(aq) + Br-(aq) → AgBr(s) + H2O(l)
The balanced net ionic equation is:
Ag+(aq) + OH-(aq) + H+(aq) + Br-(aq) → AgBr(s) + H2O(l)
(b) The balanced molecular equation for the reaction between aqueous strontium hydroxide (Sr(OH)2) and hydroiodic acid (HI) is:
Sr(OH)2 + 2HI → SrI2 + 2H2O
The balanced complete ionic equation is:
Sr2+(aq) + 2OH-(aq) + 2H+(aq) + 2I-(aq) → SrI2(s) + 2H2O(l)
The balanced net ionic equation is:
Sr2+(aq) + 2OH-(aq) + 2H+(aq) + 2I-(aq) → SrI2(s) + 2H2O(l)
(c) The balanced molecular equation for the reaction between solid iron(III) hydroxide (Fe(OH)3) and nitric acid (HNO3) is:
Fe(OH)3 + 3HNO3 → Fe(NO3)3 + 3H2O
The balanced complete ionic equation is:
Fe3+(aq) + 3OH-(aq) + 3H+(aq) + 3NO3-(aq) → Fe(NO3)3(s) + 3H2O(l)
The balanced net ionic equation is:
Fe3+(aq) + 3OH-(aq) + 3H+(aq) + 3NO3-(aq) → Fe(NO3)3(s) + 3H2O(l)
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