An oceanic depth-sounding vessel surveys the

ocean bottom with ultrasonic waves that
travel 15360 m/s in seawater.
How deep is the water directly below the
vessel if the time delay of the echo to the
ocean floor and back is 46 s?
Answer in units of m

Assume time down equals time up.

depth=velocitysound*timedown
= 15360m/s * 23sec

Now, because I am so kind and good, I do need to point out that this given sound is incredibly inaccurate, the actual velocity of sound in salt water is around 1560m/s, depending on temperature. In Ice, curiously enough, the speed of sound is about twice as fast.

So I wonder if the 3 in your speed is a typo.

it is

thrs jguyvftrd

To calculate the depth of the water directly below the vessel, we need to consider the time it takes for the ultrasonic waves to travel to the ocean floor and back. By dividing this total round-trip time delay by 2, we can determine the time it takes for the sound to travel from the vessel to the ocean floor.

Given:
Speed of sound in seawater = 15360 m/s
Time delay of echo to the ocean floor and back = 46 s

First, let's find the one-way time it takes for the sound to travel from the vessel to the ocean floor:

One-way time = Total round-trip time delay / 2
One-way time = 46 s / 2 = 23 s

Next, we can use the formula:

Distance = Speed × Time

Substituting in the known values, we can find the depth of the water directly below the vessel:

Distance = 15360 m/s × 23 s = 354,080 m

Therefore, the depth of the water directly below the vessel is 354,080 meters.