How many milliliters of 5M H2SO4 are required to make a 1500ml of a .002M H2SO4 solution.

I used the formula M*L=M * L so
mL *5 = 1500 * .002
I got .6mL is this right?

0.6 mL is correct.

Well, that equation is definitely not a joke, but your answer might be! Let's see if we can solve it together.

To find out how many milliliters of a 5M H2SO4 solution are needed to make a 1500ml of a 0.002M H2SO4 solution, we can use the formula M1V1 = M2V2.

So, substituting the values we have:
5M * V1 = 0.002M * 1500ml

Now, let's solve it:
V1 = (0.002M * 1500ml) / 5M
V1 = 0.006ml

So, it looks like your answer of 0.6ml might have been a teeny tiny exaggeration. The correct answer is 0.006ml. Just a drop in the bucket!

To calculate the amount of 5M H2SO4 required to make a 1500ml solution of 0.002M H2SO4, you can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

In this case, C1 = 5M, V1 = unknown (the volume of 5M H2SO4 we want to find), C2 = 0.002M, and V2 = 1500ml.

Rearranging the formula to solve for V1, we have:

V1 = (C2 * V2) / C1
= (0.002M * 1500ml) / 5M
= (0.003) / 5
= 0.0006 L

To convert L to mL, we multiply by 1000, so:

V1 = 0.0006 L * 1000
= 0.6 mL

Therefore, the correct answer is 0.6 mL of 5M H2SO4 is required to make a 1500ml solution of 0.002M H2SO4.

To solve this problem, you need to use the formula for dilution, which is given by the equation M1V1 = M2V2.

In this equation:
- M1 represents the initial concentration of the solution (in this case, 5M)
- V1 represents the volume of the initial solution (which is what we need to find)
- M2 represents the desired concentration of the final solution (0.002M)
- V2 represents the final volume of the solution (1500mL)

Rearranging the equation, we have:
V1 = (M2 * V2) / M1
Plugging in the given values:
V1 = (0.002M * 1500mL) / 5M
= (0.003mL * 1500)
= 4.5mL

Therefore, you would need 4.5mL of the 5M H2SO4 solution to make 1500mL of a 0.002M H2SO4 solution. Your answer of 0.6mL is incorrect.