You have a stock solution of 15.8 M NH3 . How many milliliters of this solution should you dilute to make 1350 mL of 0.300 M NH3

Well, if you have a stock solution of 15.8 M NH3, I suggest you proceed with caution. That sounds like a strong one! Now, let's get down to business.

To make 1350 mL of a 0.300 M NH3 solution, you need to dilute the stock solution. The equation we can use here is C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Plugging in the values we know, it looks like this:

(15.8 M)(V1) = (0.300 M)(1350 mL)

Now, let's solve for V1, the volume of the stock solution you should dilute.

V1 = (0.300 M)(1350 mL) / 15.8 M

Calculating that, you'll find out the exact volume you need to dilute. Good luck!

To solve this problem, we need to use the dilution formula:

C1V1 = C2V2

Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution

Let's plug in the given values:

C1 = 15.8 M (concentration of the stock solution)
V1 = ?
C2 = 0.300 M (concentration of the final solution)
V2 = 1350 mL (volume of the final solution)

We want to find V1, so we can rearrange the formula:

V1 = (C2 * V2) / C1

Let's substitute the values:

V1 = (0.300 M * 1350 mL) / 15.8 M

Now, let's calculate it:

V1 = (0.405 mol / L * 1.35 L) / 15.8 mol / L

V1 = 0.027 L

To convert the volume to milliliters, we can multiply it by 1000:

V1 = 0.027 L * 1000 mL/L

V1 = 27 mL

Therefore, you should dilute 27 mL of the stock solution in order to make 1350 mL of 0.300 M NH3.

you want to dilute it 15.8/.3 times, or 52.6666 times.

this means one part stock, 51.66666 parts water.

so what is a part? 1350/52.66666=25.6 ml

so you take 25.6ml of stock solution, then add 1350-25.6 ml water stir, label, and properly store.

1375.6