A bike first accelerates from 0.0 m/s to 5.0 m/s in 4.5 s, then continues at this constant speed for another 4.5 s. What is the total distance traveled by the bike?

phase 1

a = (5-0)/4.5 = 1.11 m/s^2
v = 0 + a t = 1.11*4.5 = 5 sure enough
d = 0 + 0 (4.5) + (1/2)(1.11)(4.5)^2 =11.2

then phase 2
a = 0
v = 5
d = 11.2 + 5 (4.5) + 0
= 11.2 + 22.5 = 33.7 meters

It's actually 33.8

thank you

did i ask?

thank you I am Russian you blyat

33.7

33.87

i’m alive

brendan a bx

To find the total distance traveled by the bike, we need to calculate the distance covered during each of the two phases: the acceleration phase and the constant speed phase.

In the acceleration phase, the bike starts from rest (0.0 m/s) and accelerates to 5.0 m/s in 4.5 seconds. Since the acceleration is constant, we can use the formula:
v = u + at
where:
v is the final velocity (5.0 m/s)
u is the initial velocity (0.0 m/s)
a is the acceleration
t is the time (4.5 s)

Rearranging the formula to solve for acceleration (a):
a = (v - u) / t

Substituting the given values:
a = (5.0 m/s - 0.0 m/s) / 4.5 s = 1.1111 m/s² (rounded to four decimal places)

Now, to find the distance covered during the acceleration phase, we can use another formula:
s = ut + (1/2)at²
where:
s is the distance
u is the initial velocity (0.0 m/s, since the bike starts from rest)
t is the time (4.5 s)
a is the acceleration (1.1111 m/s², as calculated)

Substituting the given values:
s = (0.0 m/s)(4.5 s) + (1/2)(1.1111 m/s²)(4.5 s)²
s = 0 + 0.5(1.1111 m/s²)(20.25 s²)
s = 0.5(22.4725 m)
s = 11.2363 m (rounded to four decimal places)

So, during the acceleration phase, the bike traveled 11.2363 meters.

In the constant speed phase, the bike continues to move at a constant speed of 5.0 m/s for 4.5 seconds. We can calculate the distance covered during this phase using the formula:
s = v * t
where:
s is the distance
v is the velocity (5.0 m/s)
t is the time (4.5 s)

Substituting the given values:
s = (5.0 m/s)(4.5 s)
s = 22.5 m

Therefore, during the constant speed phase, the bike traveled 22.5 meters.

To find the total distance traveled by the bike, we add the distances covered during the acceleration and constant speed phases:
Total distance = distance during acceleration + distance during constant speed
Total distance = 11.2363 m + 22.5 m
Total distance = 33.7363 m

Hence, the total distance traveled by the bike is 33.7363 meters.