a political discussion group consists of five Democrats and six Republicans. Four people are selected to attend a conference.

A.in how many ways can four people be selected from this group of eleven?

B.In how many ways can four Republicans be selected from six Republicans?

C.find the probability that the selected group will consist of all Republicans?

A) choose 4 from 11 which is C(11,4) or 330

b) choose 4 from 6 which is C(6,4) or 15

c) assuming that your group still consists of 4 people
prob = 15/330 = 1/22

A. 11 x 10 x 9 x 8/(4 x 3 x 2 x 1) = 330

B. 6!/(4!*2!) = 15

C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545

Thanks, but i need the answer to all three questions

thank you

What is the cost of concrete for a walkway that is 15 feet long, 8 feet wide, and 9 inches deep if the concrete costs $30 per cubic yard?

$100

2. To play the California lottery, a person has to correctly select 6 out of 51 numbers. What is the probability that one combination of six numbers will win? If it costs $1 to play and you receive $1,000,000 if you win, what is the expected value of the lottery?

A political discussion group consists of 6 Democrats and 10 Republicans. Five members are selected to attend a conference. Find the probability that the group will consist of all Democrats.

To solve these questions, we can use combinations and probability.

A. The number of ways to choose a group of four people from a group of eleven can be calculated using combinations. The formula for combinations is:

nCk = n! / (k!(n-k)!)

where n is the total number of people, and k is the number of people to be selected.

So, for this question, the number of ways to select four people from a group of eleven can be calculated as follows:

11C4 = 11! / (4!(11-4)!)
= 11! / (4!7!)
= (11*10*9*8) / (4*3*2*1)
= 330

Therefore, there are 330 different ways to select four people from the group of eleven.

B. To find the number of ways to select four Republicans from six Republicans, we can use the same combination formula mentioned above.

6C4 = 6! / (4!(6-4)!)
= 6! / (4!2!)
= (6*5) / (2*1)
= 15

Therefore, there are 15 different ways to select four Republicans from the group of six Republicans.

C. To find the probability that the selected group will consist of all Republicans, we divide the number of ways to select four Republicans from six Republicans (15) by the total number of ways to select four people from the group of eleven (330). The probability can be calculated as:

P(All Republicans) = (Number of ways to select four Republicans) / (Number of ways to select four people)

P(All Republicans) = 15 / 330
= 1/22

Therefore, the probability that the selected group will consist of all Republicans is 1/22.

the answer is "C"