Rust contains an iron-oxygen compound in which there are three oxygen atoms for each two iron atoms. In this compound, the iron to oxygen mass ratio is 2.325:1. Another compound of iron and oxygen contains these elements in the ratio of 2.616:1. What is the ratio of iron to oxygen atoms in the second iron-oxygen compound. Explain please each step. Thanks.
I would do this.
Convert grams to moles.
Fe2.325O1
2.325/55.85 = 0.04163
1/16 = 0.0625
Then divide EACH by the smaller value to find the ratio in small whole numbers.
0.04163/0.04163 = 1.00
0.0625/0.04163 = 1.50
And the ratio in small whole numbers is
Fe2O3 which just confirms the numbers in the problem.
Now do the same thing with the second compound.
Ah, iron and oxygen, the classic duo in the world of chemistry. Alright, let's unravel this mystery of ratios together!
First, we're given two ratios for iron to oxygen mass. In the first compound, it's 2.325:1, and in the second compound, it's 2.616:1. We want to find the ratio of iron to oxygen atoms in the second compound.
To do that, we need to compare the two ratios and find a way to connect them. We'll start with the first compound's ratio, where we have 2.325 parts of iron for every 1 part of oxygen.
Now, in the world of science, we can find the atomic masses of elements, which tells us how much each atom weighs. The atomic mass of iron (Fe) is around 55.845 g/mol, while that of oxygen (O) is around 16 g/mol.
To connect the ratios with atoms instead of mass, we need to convert the given ratio for the first compound to a ratio of moles. Let's assume that we have X moles of iron and Y moles of oxygen in the first compound. Using the atomic masses, we can set up the following equation:
2.325(X mol Fe) / 1(Y mol O) = (55.845 g/mol * X) / (16 g/mol * Y)
This equation lets us compare the two ratios using moles rather than mass. Now comes the fun part—solving the equation! We can cross-multiply the equation to get:
2.325 * 16 * Y = 55.845 * X
37.2 * Y = 55.845 * X
Dividing both sides by 37.2 gives us:
Y / X = (55.845 / 37.2)
Y / X = 1.5
So, in the first compound, the ratio of iron atoms to oxygen atoms is 1.5:1.
Now, moving on to the second compound, where the iron to oxygen mass ratio is 2.616:1. We'll use the same process, but this time, we want to find the ratio of iron to oxygen atoms.
Using the same reasoning, we can set up another equation:
2.616(X mol Fe) / 1(Y mol O) = (55.845 g/mol * X) / (16 g/mol * Y)
Cross-multiplying and simplifying gives us:
Y / X = (55.845 / 37.2)
Y / X = 1.5
Voila! The ratio of iron atoms to oxygen atoms in the second compound is also 1.5:1.
So, to summarize, the ratio of iron to oxygen atoms in both compounds is 1.5:1. I hope my little chemistry circus routine has shed some light on the topic!
To find the ratio of iron to oxygen atoms in the second iron-oxygen compound, we need to use the given mass ratios for iron and oxygen.
1. Let's assume the mass of iron in the first compound is represented by "x" and the mass of oxygen is represented by "y".
- From the given mass ratio (2.325:1), we can set up the equation:
x/y = 2.325
2. Now, let's assume the mass of iron in the second compound is represented by "a" and the mass of oxygen is represented by "b".
- From the given mass ratio (2.616:1), we can set up the equation:
a/b = 2.616
3. Since we have the mass ratios, we can solve these equations to find the ratios of iron and oxygen atoms.
- Divide equation 2 by equation 1:
(a/b)/(x/y) = 2.616/2.325
4. To divide fractions, we multiply the first fraction by the reciprocal of the second fraction:
- (a/b) * (y/x) = 2.616/2.325
5. Multiplying fractions is done by multiplying the numerators together and the denominators together:
- (ay)/(bx) = 2.616/2.325
6. Now, we simplify the ratio by dividing both sides of the equation by the greatest common divisor (GCD) of ay and bx.
- Let GCD(ay, bx) = d
- Then, we have:
(ay)/d = (2.616/2.325)(bx)/d
7. Since we assume the mass of iron and oxygen in both compounds, we can cancel out the GCD to get the ratio of iron to oxygen atoms:
- ay = (2.616/2.325)bx
8. After simplifying, the ratio of iron to oxygen atoms in the second iron-oxygen compound is:
- a/b = (2.616/2.325)
To solve this problem, we need to understand the concept of the mass ratio of elements in a compound. The mass ratio is the ratio of the masses of the two elements present.
Let's denote the first compound as Rust, where the iron-oxygen mass ratio is 2.325:1. This means that for every 2.325 grams of iron in Rust, there is 1 gram of oxygen.
Now, let's focus on the second compound, where the iron-oxygen mass ratio is 2.616:1. We need to determine the ratio of iron to oxygen atoms in this compound.
To find the ratio of iron to oxygen atoms, we need to determine the ratio of the number of moles of iron to the number of moles of oxygen in the compound.
Step 1: Determine the molecular formula for each compound.
The molecular formula tells you the actual number of atoms of each element present in the compound.
Step 2: Calculate the molar mass of each compound.
The molar mass is the mass of one mole of a substance and is expressed in grams/mol.
Step 3: Calculate the number of moles of iron and oxygen.
To find the moles of iron and oxygen, divide the mass of each element by its molar mass.
Step 4: Find the ratio of moles of iron to moles of oxygen.
Divide the number of moles of iron by the number of moles of oxygen to find the ratio of iron to oxygen atoms.
Now, let's apply these steps to find the ratio of iron to oxygen atoms in the second iron-oxygen compound mentioned in the question.
Unfortunately, we don't have enough information to directly calculate the molecular formula or molar mass of the compounds. Without this information, we cannot proceed with the specific calculation necessary to find the ratio of iron to oxygen atoms in the second compound.
However, if you are provided with the molecular formula or molar mass of the second compound, you can follow the steps outlined above to determine the ratio of iron to oxygen atoms.