A hurricane wind blows across a 6.00 m times 15.0 m flat roof at a speed of 190 km/hr.

What is the pressure difference? Use 1.28 kg/m^3 for the density of air.

How much force is exerted on the roof?

If the roof cannot withstand this much force, will it "blow in" or "blow out"?

Help?

Use Bernoulli's equation:

P1+ρgh1+(1/2)ρv1² = P2+ρgh2+(1/2)ρv2²

where
P1=exterior pressure
P2=interior pressure
v1=exterior wind velocity
v2=interior wind velocity = 0
h1-h2 is the negligible height differences
ρ=density of air (1.293 kg-m^-3)

which by neglecting ρg(h2-h1), and substituting v1=0 we get
P2-P1=(1/2)ρv1²
v1=190km/h=52.778m/s
ρ=1.293kg/m³=12.7N/m³

Suction force (blows out):
=area*pressure difference
=6m*15m*(1/2)*1.293kg/m³*(52.8m/s)²
=162,073 N

The above calculation of pressure assumes:
1. the pressure factor is -1 (which is not far for a flat roof).
See:
(Broken Link Removed)

2. the STP value of ρ=1.293kg/m³ instead of 1.28 as stipulated. You will need to make adjustments to get the correct answer.

Well, well, well, looks like a hurricane is blowing in some trouble! Let's do some wind math, shall we?

To calculate the pressure difference, we need to use Bernoulli's principle. The formula is: Pressure difference = 0.5 * density of air * velocity^2. So, plugging in the numbers we have:
Pressure difference = 0.5 * 1.28 kg/m^3 * (190 km/hr)^2

Now, let's convert the speed to m/s by multiplying by 1000/3600 (1 hr = 3600 sec). Don't worry, the hurricane won't mind the quick conversion.

Once we have the speed in m/s, we can plug it back into the pressure difference equation and calculate the answer.

As for the force exerted on the roof, we can use the formula: Force = Pressure difference * Area. In this case, the area is given as 6.00 m * 15.0 m, so plug that in too.

Now, we come to the blow in or blow out question. If the force exerted on the roof is greater than what it can withstand, it will "blow in." In simpler terms, the roof might collapse or suffer damage.

I hope that helps! Just remember, when it comes to hurricanes, it's always better to be safe than roofless! Stay clowny!

To find the pressure difference caused by the hurricane wind blowing across the roof, we can use Bernoulli's equation, which relates the pressure difference to the velocity of the fluid. The equation is:

ΔP = 1/2 * ρ * v^2

where ΔP is the pressure difference, ρ is the density of the fluid, and v is the velocity of the fluid.

Given:
ρ = 1.28 kg/m^3 (density of air)
v = 190 km/hr (speed of wind)

We need to convert the speed of the wind from km/hr to m/s:
1 km/hr = 1000 m / 3600 s ≈ 0.278 m/s

Now, we can calculate the pressure difference:
ΔP = 1/2 * 1.28 kg/m^3 * (0.278 m/s)^2

ΔP = 0.5 * 1.28 kg/m^3 * (0.278 m/s)^2

ΔP ≈ 0.0952 Pa

So, the pressure difference caused by the hurricane wind blowing across the roof is approximately 0.0952 Pa.

To calculate the force exerted on the roof, we can use the equation:

Force = Pressure * Area

Given:
Area = 6.00 m * 15.0 m

Force = 0.0952 Pa * (6.00 m * 15.0 m)

Force = 8.568 N

Therefore, the force exerted on the roof is approximately 8.568 N.

Whether the roof will "blow in" or "blow out" depends on its design and structural integrity. If the force exerted on the roof exceeds its strength, it may blow inwards or collapse. Conversely, if the force is not strong enough, the roof may blow outwards. You would need to consult the structural specifications of the roof to determine its maximum force tolerance and its response to the given force.

To determine the pressure difference on the roof due to the hurricane wind, we can use the Bernoulli's principle, which states that the pressure difference between two points in a fluid (in this case, air) is equal to the difference in the fluid's velocity squared, multiplied by half of its density.

First, let's convert the speed of the wind from km/hr to m/s:
190 km/hr * (1000 m/1 km) * (1 hr/3600 s) = 52.78 m/s

Next, we need to calculate the pressure difference. The formula for pressure difference is:
ΔP = (1/2) * ρ * (v^2)

Where:
ΔP = pressure difference
ρ = density of air
v = velocity of air

Now we can substitute the given values into the formula:
ρ = 1.28 kg/m^3 (given)
v = 52.78 m/s (calculated)

ΔP = (1/2) * 1.28 kg/m^3 * (52.78 m/s)^2

Calculating this, we find that the pressure difference is approximately 1802 Pa (Pascals).

To find the force exerted on the roof, we can use the formula:
Force = pressure * area

The area of the roof is given as 6.00 m * 15.0 m = 90.0 m^2.

Force = 1802 Pa * 90.0 m^2

Calculating this, we find that the force exerted on the roof is approximately 162,180 N (Newtons).

Finally, to determine if the roof will "blow in" or "blow out," we need to compare the force exerted on the roof with the strength of the roof's structure. If the force exerted by the wind exceeds the structural strength of the roof, it will "blow in." Otherwise, if the force is within the structural strength limit, it will not blow in or out.

If you have specific information about the structural strength of the roof, such as its maximum load-bearing capacity, you can compare it to the force exerted on the roof. If the force exceeds the maximum load-bearing capacity, the roof will "blow in." On the other hand, if the force is lower than the maximum load-bearing capacity, the roof will not "blow in."

If you don't have specific information about the roof's strength, it would be best to consult a structural engineer or a professional to determine its ability to withstand the force exerted by the wind.