Sodium carbonate reacts with hydrochloric acid as shown below in an unbalanced chemical equation. What mass of CO2 is produced from the reaction of 2.94g Na2CO3 with excess HCL?
I have answered three times here and nothing posts. Try again.
The balanced equation is
Na2CO3 + 2HCl ==> 2NaCl + H2O + CO2
Here is a worked example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
What mass of CO2 is produced from the reaction of 2.94 g Na2CO3 with excess HCl?
it is 1.22 g. CO2
Mama: NO
Mama's son: FINE
Well, it looks like sodium carbonate (Na2CO3) is having a little party with hydrochloric acid (HCl). Now, to figure out how much CO2 they're going to produce, we need to balance this equation and whip out our calculators.
First, we need to balance the equation. It goes something like this:
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
Now we have a balanced equation! Time to do some math.
To find out how much CO2 is produced from 2.94g of Na2CO3, we need to use stoichiometry, which is like chemistry's version of using a road map.
The molar mass of Na2CO3 is 105.99 g/mol, and from the balanced equation, we can see that 1 mole of Na2CO3 produces 1 mole of CO2.
So, to find the number of moles of Na2CO3, we divide the mass by the molar mass:
2.94g Na2CO3 / 105.99 g/mol = 0.0277 moles Na2CO3
Since the molar ratio between Na2CO3 and CO2 is 1:1, we can conclude that we'll have 0.0277 moles of CO2.
Finally, to find the mass of CO2, we multiply the number of moles by the molar mass of CO2, which is 44.01 g/mol:
0.0277 moles CO2 * 44.01 g/mol ≈ 1.22 g CO2
So, my friend, by crunching the numbers, we can say that approximately 1.22 grams of CO2 will be produced from the reaction of 2.94 grams of Na2CO3 and an excess of HCl. Enjoy the fizz!
To determine the mass of CO2 produced from the reaction, we first need to balance the chemical equation. The unbalanced equation is:
Na2CO3 + HCl -> CO2 + NaCl + H2O
To balance the equation, we need to ensure that the number of each type of atom is the same on both sides. Here's the balanced equation:
Na2CO3 + 2HCl -> CO2 + 2NaCl + H2O
From the balanced equation, we can see that 1 mole of Na2CO3 reacts with 2 moles of HCl to produce 1 mole of CO2.
Let's calculate the moles of Na2CO3 using its molar mass:
Molar mass of Na2CO3 = 22.99 g/mol (2 Na) + 12.01 g/mol (C) + 3(16.00 g/mol) (3 O) = 105.99 g/mol
Moles of Na2CO3 = mass / molar mass = 2.94 g / 105.99 g/mol
Now, we can use the mole ratio from the balanced equation to find the moles of CO2 produced. From the equation, we know that 1 mole of Na2CO3 produces 1 mole of CO2. Therefore, the moles of CO2 produced are also equal to 2.94 g / 105.99 g/mol.
Finally, we can calculate the mass of CO2 produced using the molar mass of CO2:
Molar mass of CO2 = 12.01 g/mol (C) + 2(16.00 g/mol) (2 O) = 44.01 g/mol
Mass of CO2 produced = moles of CO2 produced * molar mass of CO2
Now, you can substitute the values into the equation and solve for the mass of CO2 produced.