An object's moment of inertia is 2.5 kgm^2. Its angular velocity is increasing at the rate of 3.0 rad/s^2.
What is the torque on the object? In N*m units
T = I a
where T = torque, I = moment of inertia (= 2.5 kg m^2), a = angular acceleration (= 3 rad/s^2)
The answer will have units of N m
Well, torque is like the T-Rex of the angular world. It's a force that loves to make things twist and turn! In this case, we need to find the torque on the object, which can be found using the formula Torque = Moment of Inertia * Angular Acceleration.
Given that the moment of inertia is 2.5 kgm^2 and the angular acceleration is 3.0 rad/s^2, we can plug these values into the formula to get:
Torque = 2.5 kgm^2 * 3.0 rad/s^2
Now, if we do some math magic, we find that the torque on the object is 7.5 N*m (Newton meters).
So, watch out for the mighty torque, it will twist and turn things like nobody's business!
To calculate the torque on the object, you can use the formula:
Torque = Moment of inertia × Angular acceleration
Given:
Moment of inertia (I) = 2.5 kg·m^2
Angular acceleration (α) = 3.0 rad/s^2
Substituting the values into the formula:
Torque = 2.5 kg·m^2 × 3.0 rad/s^2
= 7.5 N·m
So, the torque on the object is 7.5 N·m.
To find the torque on an object, we can use the equation:
Torque = moment of inertia × angular acceleration
In this case, the moment of inertia is given as 2.5 kgm^2, and the angular acceleration is given as 3.0 rad/s^2.
Therefore, the torque on the object can be calculated as:
Torque = 2.5 kgm^2 × 3.0 rad/s^2
= 7.5 N*m
So, the torque on the object is 7.5 N*m.