sample of liquid water at 100 degrees C absorbs 113 kJ of heat. HOw much water will be converted to steam heat vaporization if water is 2.26 kJ/g
I just need help with what formula to set this up
Wouldn't 2.26 kJ/g x #g = 113 kJ? Solve for #g.
no
To find out how much water will be converted to steam during the process, you can use the formula:
Amount of water converted to steam = Total heat absorbed / Heat of vaporization
In this case, the total heat absorbed is given as 113 kJ, and the heat of vaporization is given as 2.26 kJ/g.
To use this formula, you need to convert the total heat and heat of vaporization to the same unit. Assuming the heat of vaporization is given in kJ/g, we will convert the total heat from kJ to grams of water.
The conversion factor for water is that 1 g of water absorbs 1 kJ of heat. Therefore, we can convert the heat absorbed from kJ to grams by multiplying it by 1 g/kJ.
So, the formula becomes:
Amount of water converted to steam = (Total heat absorbed in grams) / Heat of vaporization
Total heat absorbed in grams = Total heat absorbed in kJ * 1 g/kJ
Plugging in the values:
Total heat absorbed in grams = 113 kJ * 1 g/kJ = 113 g
Amount of water converted to steam = 113 g / 2.26 kJ/g
Now you can calculate the amount of water that will be converted to steam:
Amount of water converted to steam = 113 g / 2.26 kJ/g = 50 g
Therefore, during the process, 50 grams of water will be converted to steam.
To calculate the amount of water vaporized given the heat absorbed and the heat of vaporization, you can use the formula:
Amount of water vaporized (in grams) = Heat absorbed / Heat of vaporization
Given:
Heat absorbed = 113 kJ
Heat of vaporization = 2.26 kJ/g
Substitute these values into the formula:
Amount of water vaporized = 113 kJ / 2.26 kJ/g
Now, calculate the result:
Amount of water vaporized = 50 grams
Therefore, 50 grams of water will be converted to steam.