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Prove each identity:

a) 1-cos^2x=tan^2xcos^2x
b) cos^2x + 2sin^2x-1 = sin^2x

I also tried a question on my own:
tan^2x = (1 – cos^2x)/cos^2x
R.S.= sin^2x/cos^2x
I know that the Pythagorean for that is sin^2x + cos^2x
That's all I could do.

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1 answer
  1. a)
    Given tan(θ)=sin(θ)/cos(θ)
    substitute tan(θ) by sin(θ)/cos(θ) on the RHS and see what you get.

    b) hint:
    cos(2θ)=cos²(θ)-sin²(θ)

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