how do i write a net ionic equation for Lead (II) Nitrate and Sodium Carbonate react to form Lead Carbonate and Sodium Nitrate??

Step 1. Write molecular equation:

Pb(NO3)2(aq) + Na2CO3(aq) ==> PbCO3(s) + 2NaNO3(aq)

Step 2. Separate into ions; e.g., Pb^+2(aq) + 2NO3^-(aq) + etc. Solids (those with (s) are not soluble; therefore, do not separate them. Any weak electrolytes also stay as the molecule; you don't have any of those in this equation.

Step 3. Cancel any ions common to both sides. What remains is the net ionic equation.

I will give you the completed equation BUT you should go through to make sure you can do these.
Pb^+2(aq) + CO3^-2(aq) ==> PbCO3(s)

Note that the Na^+ and the NO3^- ions cancel; they don't enter into the reaction.

pipi

Oh boy, let's get the chemical circus started! Here's the humorous net ionic equation for you:

Pb(NO3)2 (aq) + Na2CO3 (aq) ⟶ PbCO3 (s) + 2 NaNO3 (aq)

And the clowns take center stage! Lead (II) Nitrate meets Sodium Carbonate, which causes a chemical reaction! Out pops Lead Carbonate, ready to shine in the spotlight, while Sodium Nitrate dances around excitedly. Bravo!

To write a net ionic equation, you need to first write the balanced chemical equation for the reaction between Lead (II) Nitrate (Pb(NO3)2) and Sodium Carbonate (Na2CO3), and then identify the complete ionic equation by separating the reactants and products into their respective ions. Finally, you can cancel out the spectator ions to obtain the net ionic equation.

Let's go step by step:

Step 1: Write the balanced chemical equation:
Pb(NO3)2 + Na2CO3 → PbCO3 + 2NaNO3

Step 2: Write the complete ionic equation by separating the reactants and products into their respective ions:
Pb^2+ (aq) + 2NO3^- (aq) + 2Na^+ (aq) + CO3^2- (aq) → PbCO3 (s) + 2Na^+ (aq) + 2NO3^- (aq)

Step 3: Identify the spectator ions, which are the ions that appear on both sides of the equation without undergoing any change:
In this case, the spectator ions are Na^+ and NO3^-.

Step 4: Cancel out the spectator ions to obtain the net ionic equation:
Pb^2+ (aq) + CO3^2- (aq) → PbCO3 (s)

The net ionic equation for the reaction between Lead (II) Nitrate and Sodium Carbonate to form Lead Carbonate and Sodium Nitrate is Pb^2+ (aq) + CO3^2- (aq) → PbCO3 (s).

Doesn’t wor