What is the molar mass of anhydrous salt in CuSo4 5H2O
Ah, the molar mass of anhydrous salt in CuSO4·5H2O, you ask? Well, buckle up, my friend! CuSO4·5H2O is like a fancy party - it's got several guests.
First, we have Copper (Cu) with a molar mass of 63.55 grams per mole. Then, there's Sulfur (S) with a molar mass of 32.06 grams per mole. Lastly, we have Oxygen (O) with a molar mass of 16.00 grams per mole.
But wait, the party is not over yet! We also have some water (H2O) molecules crashing in. Each water molecule contains two Hydrogen (H) atoms at a molar mass of 1.01 grams per mole and one Oxygen (O) atom.
Now, let's calculate the total molar mass of CuSO4·5H2O!
Copper (Cu): 1 × 63.55 = 63.55g/mole
Sulfur (S): 1 × 32.06 = 32.06g/mole
Oxygen from CuSO4: 4 × 16.00 = 64.00g/mole
Oxygen from H2O: 5 × (16.00 + 1.01 + 1.01) = 101.00g/mole
Hydrogen from H2O: 5 × 2 × 1.01 = 10.10g/mole
Now, let's add them all up!
Molar mass of CuSO4·5H2O = 63.55 + 32.06 + 64.00 + 101.00 + 10.10 = 270.71 grams per mole.
So, the molar mass of anhydrous salt in CuSO4·5H2O is 270.71 grams per mole. Quite a mouthful, isn't it?
To find the molar mass of the anhydrous salt in CuSO4 · 5H2O, we need to calculate the sum of the molar masses for all the atoms in the compound.
The molar mass of copper (Cu) is approximately 63.55 g/mol.
The molar mass of sulfur (S) is approximately 32.07 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
The molar mass of hydrogen (H) is approximately 1.01 g/mol.
For the water molecules, we need to consider the molar masses of hydrogen and oxygen:
Molar mass of water (H2O):
2 (molar mass of hydrogen) + 1 (molar mass of oxygen) = 2.02 + 16.00 = 18.02 g/mol.
Since there are five water molecules in the compound (CuSO4 · 5H2O), the total mass contributed by the water is:
5 (number of water molecules) × 18.02 (molar mass of water) = 90.1 g/mol.
Now, let's calculate the molar mass of the anhydrous salt:
Molar mass = Molar mass of Cu + Molar mass of S + 4 × Molar mass of O + Total mass contributed by water
= 63.55 + 32.07 + 4 × 16.00 + 90.1
= 159.55 g/mol.
Therefore, the molar mass of the anhydrous salt in CuSO4 · 5H2O is approximately 159.55 g/mol.
To determine the molar mass of anhydrous salt, CuSO4, first, we need to understand the concept of molar mass. The molar mass of a compound is the sum of the atomic masses of all the atoms in its chemical formula.
To find the molar mass of CuSO4, we need to consider the atomic masses of each element in the formula.
The atomic masses of copper (Cu), sulfur (S), and oxygen (O) can be found on the periodic table. The atomic mass of copper is 63.55 g/mol, sulfur is 32.07 g/mol, and oxygen is 16.00 g/mol.
The chemical formula CuSO4 indicates that there is one copper atom (Cu), one sulfur atom (S), and four oxygen atoms (O) in each molecule of CuSO4.
To calculate the molar mass, we multiply the atomic masses of each element by the number of atoms present, and then sum them up:
Molar mass of CuSO4 = (Atomic mass of Cu) + (Atomic mass of S) + 4 * (Atomic mass of O)
Molar mass of CuSO4 = (63.55 g/mol) + (32.07 g/mol) + 4 * (16.00 g/mol)
Molar mass of CuSO4 = 63.55 g/mol + 32.07 g/mol + 64.00 g/mol
Molar mass of CuSO4 = 159.62 g/mol
So, the molar mass of anhydrous salt in CuSO4 is 159.62 g/mol.
Anhydrous salt = CuSO4
Cu: 63.55g/mol
S: 32.07g/mol
O: 4(16.00g/mol)
So:
63.55g/mol
32.07g/mol
+64.00g/mol
=159.62g/mol