25cm3 of a solution of 0.1mol dm-3 NaoH reacts with 50cm3 of a solution of hydrochloric acid.What is the molarity of the acid
is there any way i can see an answer for this.. i have it as an a level chemistry question and im either having a mental block... or totallyyy don't get it ?
this does not give the answer
0.05m/l
C(a)×V(a)=c(b)xv(b)
0.025dm-3x0.1mol=0.050dm-3x zmol
0.00025=0.050z
2.5/50=z
0.05mols/50cm-³
Write the equation and balance it.
HCl + NaOH ==> NaCl + H2O
How many moles NaOH were used? moles = M x L = ??
Using the coefficients in the balanced equation, convert moles NaOH to moles HCl. You can see that it is a 1:1 ratio of NaOH to HCl; therefore, moles NaOH = moles HCl.
Then M HCl = moles HCl/L HCl. You know mole and L, solve for M.