25cm3 of a solution of 0.1mol dm-3 NaoH reacts with 50cm3 of a solution of hydrochloric acid.What is the molarity of the acid

is there any way i can see an answer for this.. i have it as an a level chemistry question and im either having a mental block... or totallyyy don't get it ?

this does not give the answer

0.05m/l

C(a)×V(a)=c(b)xv(b)

0.025dm-3x0.1mol=0.050dm-3x zmol
0.00025=0.050z
2.5/50=z
0.05mols/50cm-³

Write the equation and balance it.

HCl + NaOH ==> NaCl + H2O

How many moles NaOH were used? moles = M x L = ??
Using the coefficients in the balanced equation, convert moles NaOH to moles HCl. You can see that it is a 1:1 ratio of NaOH to HCl; therefore, moles NaOH = moles HCl.
Then M HCl = moles HCl/L HCl. You know mole and L, solve for M.

25cm3 of 1.5 solution of Nacl are added to 50cm3 of 3m Nacl. The molar concentration of the resulting solution is_

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