a cube shaped box is 6 inches wide and the rectangular box is 10 inches long, 4 inches wide, and 4 inches high. how much greater is the volume of the cube shaped box than the rectanglar box?
Volume of the cube box:
V1=6^3=216 in^3
Volume of the rectanglar box:
V2=a*b*c=10*4*4=40*4=160 in^3
V1-V2=216-160=56 in^3
To find the volume of a cube, you need to know the length of one side. In this case, you are given that the cube-shaped box is 6 inches wide. Since all sides of a cube are equal, the length, width, and height of the cube are all 6 inches.
To find the volume of a cube, you use the formula V = s^3, where V represents volume and s represents the length of one side.
Plug in the given value for the length of one side:
V_cube = 6^3 = 216 cubic inches
To find the volume of a rectangular box, you need to multiply the length, width, and height. In this case, the rectangular box has dimensions of 10 inches (length), 4 inches (width), and 4 inches (height).
Use the formula V = lwh:
V_rectangular = 10 * 4 * 4 = 160 cubic inches
To find the difference in volume between the two boxes, subtract the volume of the rectangular box from the volume of the cube-shaped box:
Difference = V_cube - V_rectangular
Difference = 216 - 160
Difference = 56 cubic inches
Therefore, the volume of the cube-shaped box is 56 cubic inches greater than the volume of the rectangular box.