bornite(Cu3FeS3)is copper ore used in the production of copper.when heated,the following reaction occurs.2CuFeS3(s)+7oxygen(g)=6Cu(s)+2FeO(s)+6SO2(g)..IF 3.88 metric tons of bornite is reacted with excess oxygen and the process has 75.6 percent yield of copper,what mass of copper in metric is produced ?
Well, well, well, we have a chemical reaction going on! Quite a fiery situation indeed. Let's crunch some numbers and figure out how much copper we've got.
First things first, we need to determine how much copper is produced from 3.88 metric tons of bornite. So let's get started!
The chemical equation tells us that for every 2 moles of CuFeS3 reacted, we get 6 moles of Cu. But we need to convert our given mass into moles.
The molar mass of CuFeS3 can be calculated as follows:
Cu: atomic mass of 63.55 g/mol
Fe: atomic mass of 55.85 g/mol
S: atomic mass of 32.07 g/mol
Adding them all up gives us: 63.55 * 3 + 55.85 + 32.07 * 3 = 249.45 g/mol
Now, we divide the total mass by the molar mass to get the number of moles:
3.88 metric tons = 3.88 * 1000 kg = 3880 kg
Moles of CuFeS3 = 3880 kg / (249.45 g/mol) = 15.55 mol
According to the reaction, we know that for every 2 moles of CuFeS3, we get 6 moles of Cu. So we multiply the number of moles of CuFeS3 by the mole ratio:
Moles of Cu = 15.55 mol * (6 mol/2 mol) = 46.65 mol
Now, to find the mass of copper produced, we multiply the moles of Cu by the molar mass of Cu:
Molar mass of Cu = 63.55 g/mol
Mass of Cu = 46.65 mol * 63.55 g/mol = 2963.58 g
But hold your horses! We need the answer in metric tons, not grams. So let's convert grams to metric tons:
Mass of Cu = 2963.58 g = 2.96358 metric tons
So, my copper-loving friend, approximately 2.96358 metric tons of copper will be produced from 3.88 metric tons of bornite. I hope these calculations didn't drive you...copper-nuts!
To find the mass of copper produced, we need to follow these steps:
Step 1: Determine the molar mass of bornite (Cu3FeS3).
- Molar mass of Cu = 63.55 g/mol
- Molar mass of Fe = 55.85 g/mol
- Molar mass of S = 32.06 g/mol
- Total molar mass of Cu3FeS3:
= (3 * 63.55) + (1 * 55.85) + (3 * 32.06)
= 63.55 * 3 + 55.85 + 32.06 * 3
= 190.65 + 55.85 + 96.18
= 342.68 g/mol
Step 2: Calculate the moles of bornite (Cu3FeS3).
- Moles = mass / molar mass
- Given mass of bornite = 3.88 metric tons = 3.88 x 10^6 g
- Moles of Cu3FeS3 = (3.88 x 10^6) / 342.68
Step 3: Determine the stoichiometry of the reaction.
- From the balanced equation: 2CuFeS3(s) + 7O2(g) → 6Cu(s) + 2FeO(s) + 6SO2(g)
- For every 2 moles of CuFeS3, 6 moles of Cu are produced.
Step 4: Calculate the moles of copper produced.
- Moles of Cu = (Moles of Cu3FeS3) × (6 moles of Cu / 2 moles of CuFeS3)
Step 5: Calculate the mass of copper produced.
- Mass of Cu = Moles of Cu × Molar mass of Cu
Step 6: Apply the 75.6% yield.
- Mass of copper produced = 75.6% × Mass of Cu (from Step 5)
Now, let's calculate the mass of copper produced:
Step 2: Moles of Cu3FeS3 = (3.88 x 10^6) / 342.68
= 11325.14 mol
Step 4: Moles of Cu = 11325.14 mol × (6 mol Cu / 2 mol CuFeS3)
= 11325.14 mol × 3
= 33975.42 mol
Step 5: Mass of Cu = 33975.42 mol × 63.55 g/mol
= 2159063.67 g
= 2159.06 kg
= 2.159 metric tons
Step 6: Mass of copper produced = 75.6% × 2159.06 kg
= 1634.8 kg
= 1.6348 metric tons
Therefore, the mass of copper produced is 1.6348 metric tons.
To find the mass of copper produced, we'll follow these steps:
Step 1: Determine the molar mass of CuFeS3
- The molar mass of CuFeS3 can be calculated by finding the molar masses of each element in the compound and multiplying by their respective subscripts.
- The molar mass of copper (Cu) is 63.55 g/mol, iron (Fe) is 55.845 g/mol, and sulfur (S) is 32.06 g/mol.
- The molar mass of CuFeS3 is (3 * 63.55) + (1 * 55.845) + (3 * 32.06) = 342.21 g/mol.
Step 2: Calculate the number of moles of CuFeS3 reacted
- Given that the mass of bornite (Cu3FeS3) is 3.88 metric tons, which is equivalent to 3.88 * 1000 * 1000 g (since 1 metric ton = 1000 kg = 1000 * 1000 g).
- The number of moles can be calculated by dividing the mass in grams by the molar mass of CuFeS3: moles = mass / molar mass.
- Thus, the moles of CuFeS3 = (3.88 * 1000 * 1000 g) / 342.21 g/mol.
Step 3: Calculate the theoretical yield of copper
- According to the balanced chemical equation, 2 moles of CuFeS3 produce 6 moles of Cu.
- Since the molar ratio is 2:6, we can calculate the theoretical yield of copper by multiplying the moles of CuFeS3 by the ratio (6/2): theoretical yield of Cu = moles of CuFeS3 * (6/2).
Step 4: Calculate the actual yield of copper based on the given percent yield
- The given percent yield is 75.6 percent, which means that only 75.6 percent of the theoretical yield is obtained.
- The actual yield of copper can be calculated by multiplying the theoretical yield by the percent yield (in decimal form): actual yield of Cu = theoretical yield of Cu * (percent yield / 100).
Step 5: Convert the mass of copper from grams to metric tons
- The mass of copper will be obtained in grams from Step 4.
- To convert grams to metric tons, divide the mass in grams by 1000 * 1000.
Now, let's perform the calculations:
Step 1: Molar mass of CuFeS3 = 342.21 g/mol
Step 2: Moles of CuFeS3 = (3.88 * 1000 * 1000 g) / 342.21 g/mol
Step 3: Theoretical yield of Cu = moles of CuFeS3 * (6/2)
Step 4: Actual yield of Cu = theoretical yield of Cu * (75.6 / 100)
Step 5: Convert mass to metric tons = actual yield of Cu / (1000 * 1000)
After performing these calculations, you will obtain the mass of copper (Cu) produced.
Your formula for bornite in the reaction is incorrect. You forgot the 3 after Cu
The molar mass of Cu3FeS3 is 342.53
The molar mass of Cu is 63.55
In a completed reaction. 2 moles (684.06 g) of Cu3FeS3 would produce 6 moles (381.30 g) of Cu. That means 55.7% of the bornite mass would become Cu. With a 75.6% yield, that ratio becomes 0.756 x 0.557 or 42.4%
From 3.88 metric tons of bornite, 1.64 tons of pure copper would be produced.