The density of aluminum is 2.70g/cm3. If a cube of aluminum weighs 13.5 grams whatis the length of the edge of the cube. I need help with the formula to figure this one out.
Close but no cigar.
Volume = mass/density = 13.5/2.7 = 5.0 cc whis is ok to this point. Now,
volume = L x L x L
5 = L x L x L
5 = L3; therefore,
L = cube root 5 OR
L = 51/3
(On your calculator, enter 5, then punch the y^x button, and type in .33333 (which is 1/3) and = to find the answer of 1.70997 which rounds to 1.71 cm to three significant figures.
Hello Dr Bob,, I am still a little confused is this what it will look like 13.5/2.70=5 then take 5*5*5=125
Thank you DR Bob
81 g
Aluminum has a density of 2.7 g/mL. What is the volume of an aluminum Cube that has a mass of 12.7 grams
mass = volume x density
since this is a cube the length,width and height are
equal so volume =L ×W×H but since L=W=H
volume = mass/density
= 12,7÷2,7
= 4,703703704
4,703703704 = L^3
L = 1,675508565cm
I need help with d first chemistry question on thi page
To find the length of the edge of the cube, we can use the formula:
Density = mass / volume
First, let's calculate the volume of the cube. Since it is a cube, all sides have the same length, denoted by "s".
The volume of a cube is given by the formula:
Volume = s^3
Now, let's substitute the given values into the formula:
13.5 grams = (2.70 grams/cm^3) x (s^3)
To isolate "s^3" on one side, divide both sides of the equation by the density:
13.5 grams / (2.70 grams/cm^3) = s^3
Now, simplify the equation:
5 cm^3 = s^3
To find "s" (the length of the edge of the cube), we can take the cubic root of both sides:
∛(5 cm^3) = ∛(s^3)
Therefore, the length of the edge of the cube is approximately 1.71 cm.
mass = volume x density
Solve for volume.
Then, since this is a cube, the length, width, and height are equal. So
volume = L x W x H but since L = W = H, then
volume = L x L x L. Solve for L.