the speed of a bullet of mass is 40gram is 216km/h what is the kinetic energy in joule

V = 216,000m/h * (1h/3600/s) = 60m/s.

mass = 40g / 1000g/kg = 0.04kg.

KE=0.5mV^2=0.5 * 0.04 * 60^2=72 Joules.

72 joules

To calculate the kinetic energy of an object, you need to know its mass and velocity. In this case, the mass of the bullet is given as 40 grams (0.04 kg) and the velocity is given as 216 km/h.

First, we need to convert the velocity from km/h to m/s since the SI unit for velocity is meters per second. To do this, we divide the velocity in km/h by 3.6 (since 1 km/h = 3.6 m/s):

Velocity in m/s = 216 km/h / 3.6 = 60 m/s

Now that we have the velocity in m/s, we can calculate the kinetic energy using the formula:

Kinetic Energy = (1/2) * mass * velocity^2

Substituting the given values:

Kinetic Energy = (1/2) * 0.04 kg * (60 m/s)^2

Simplifying this expression:

Kinetic Energy = (1/2) * 0.04 kg * 3600 m^2/s^2

Kinetic Energy = 720 J

Therefore, the kinetic energy of the bullet is 720 Joules.

K.E

what is the kinetic energy of a bullet of mass 40g mounting with a speed of 250kmh

I said 20 g not 40 g

60×72×4=16800