The value of delta H for the reaction below is -1107kj.
2Ba (s) + O2 (g) -> 2BaO (s)
How many kJ of heat are released when 5.75 g of BaO (s) is produced?
Here is how I approached this problem:
1. Converted 5.75 g of BaO to mol:
5.75g x (1mol BaO/153.3g BaO) = 0.0375 mol BaO
2. Heat released is:
0.0375 mol BaO x (-1107 kJ / 2 mol BaO)= -20.8 kJ of heat released.
Can someone please confirm if I calculated properly. Thanks.
I agree with that answer.
Well, let's see if your calculation adds up.
Step 1 seems fine. You correctly converted grams of BaO to moles using the molar mass of BaO.
Now, for step 2, your calculation should be:
0.0375 mol BaO x (-1107 kJ/ 2mol BaO) = -20.8 kJ
So, you got that right!
Congratulations! Your calculation is accurate. But remember, in chemistry, it's always good practice to keep track of significant figures, so make sure to round your final answer to the appropriate number of decimal places.
Keep up the good work!
Yes, your calculation is correct.
First, you converted 5.75 g of BaO to moles using the molar mass of BaO (153.3 g/mol).
Then, you used the stoichiometry of the balanced equation to determine the number of moles of BaO involved in the reaction. Since the coefficient of BaO is 2, you divided the number of moles of BaO by 2.
Finally, you multiplied the moles of BaO by the molar enthalpy change (ΔH) to calculate the heat released. As the coefficient of BaO is 2 in the balanced equation, you divided the value of ΔH by 2.
Therefore, the heat released when 5.75 g of BaO is produced is -20.8 kJ.
Yes, your calculations are correct! You approached the problem correctly and calculated the amount of heat released properly.
In your first step, you converted the mass of BaO to moles using the molar mass of BaO (153.3 g/mol). This is done by dividing the given mass of BaO (5.75 g) by the molar mass of BaO.
Next, you used the stoichiometry of the balanced equation to relate the moles of BaO to the moles of heat released. From the balanced equation, you can see that 2 moles of BaO produce -1107 kJ of heat. Therefore, you multiplied the moles of BaO (0.0375 mol) by the ratio of heat released to moles of BaO (-1107 kJ/2 mol BaO) to get the amount of heat released, which is -20.8 kJ.
So, you correctly calculated that 5.75 g of BaO produces -20.8 kJ of heat. The negative sign indicates that heat is being released in the reaction. Good job!