The function h is defined by h(x)=x^(2)-x.
Find h(2x).
(2x)^2-2x=4x^2-2x
Substitute 2x for x into the function, which would leave you:
h(x)=(2x)^2-2x
Factor out a 2x.
H(x)=2x(x-1) then set 2x and x-1 both equal to 0.
2x=0 x-1=0
x= 0 x=1
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Thanks I agree Reiny
To find h(2x), we need to substitute the value 2x into the function h(x) and simplify the expression.
Given that h(x) is defined as h(x) = x^2 - x, we substitute 2x into the function:
h(2x) = (2x)^2 - 2x
Now we simplify the expression:
h(2x) = 4x^2 - 2x
So, h(2x) is equal to 4x^2 - 2x.