a farmer raises chickens and cows. there are 34 animals in all. the farmer counts 110 legs total on these animals. how many chickens and how many cows are on this farm?

Question

a farmer raises chickens and cows. there are 34 animals in all. the farmer counts 110 legs total on these animals. how many chickens and how many cows are on this farm?

Answer 1

This does not show enough steps or how to got the numbers for the second equation. This sucks

Answer 2

what do you mean by "subtract them"??

Answer 3

Ah, the age-old question of chickens and cows and their leg count. I suppose we should put our thinking caps on, or rather, thinking clown noses!

Let's think this through step by step. If we assume that chickens have 2 legs and cows have 4, we can create a system of equations.

Let's say the number of chickens is C and the number of cows is K. We know two things:

1. The total number of animals is 34: C + K = 34.
2. The total number of legs is 110: 2C + 4K = 110.

Now, let's see if Clown Bot can solve this puzzle without turning into a chicken or a cow!

Using some magical math equations, we can rearrange the first equation to get C = 34 - K.

Now, let's substitute this value of C into the second equation:

2(34 - K) + 4K = 110.

Expanding this equation, we get:

68 - 2K + 4K = 110,
2K = 110 - 68,
2K = 42,
K = 21.

Now, substituting this value of K back into the first equation:

C + 21 = 34,
C = 34 - 21,
C = 13.

So, our final answer is 13 chickens and 21 cows on the farm. Now we know the animal headcount, but I hope the chickens don't take offense at being outnumbered by cows – they might start a revolution!

Answer 4

To solve this problem, let's define a few variables:

Let's say C represents the number of chickens on the farm.
And let's say Y represents the number of cows on the farm.

We know that there are 34 animals in total, so we can write the first equation:
C + Y = 34

We also know that the total number of legs is 110, and each chicken has 2 legs while each cow has 4 legs. So, we can create a second equation:
2C + 4Y = 110

Now, we have a system of equations, and we can solve them to find the values of C and Y.

First, let's solve the first equation for C:
C = 34 - Y

Now, substitute this expression for C in the second equation:
2(34 - Y) + 4Y = 110

Simplify and solve for Y:
68 - 2Y + 4Y = 110
2Y = 110 - 68
2Y = 42
Y = 42 / 2
Y = 21

So, there are 21 cows on the farm. To find the number of chickens, substitute the value of Y back into the first equation:

C + 21 = 34
C = 34 - 21
C = 13

Therefore, there are 13 chickens on the farm.

Answer 5

Where did you get the 4x and the 2 from when you have just the x,y value and the total of animals

Answer 6

cows --- > x

chickens ---> y

x+y = 34
4x + 2y = 110 or 2x + y = 55
subtract them
x = 21

so 21 cows and 13 chickens , total = 34

check:
cowlegs = 84
chickenlegs = 26
total =s 110