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1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact values of sin(theta), csc(theta), and cot(theta).

2. Let (theta) be an angle in quadrant IV such that sin(theta)=-2/5. Find the exact values of sec(theta) and tan(theta).

3. Let (theta) be an angle in quadrant II such that csc(theta)=7/4. Find the exact values of tan(theta) and cos(theta).
4. Use a cofunction to write an expression equal to csc(3pi/8).

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3 answers

  1. pls

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  2. no

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  3. 1. (-7,4) is in quadrants II,
    so x=-7, y = 4
    by Pythagoras, r = √(49 = 16) = √65

    sinØ = y/r = 4/√65
    cscØ = r/y = √65/4
    cotØ = x/y = -7/4

    2. since sinØ = -2/5 and Ø is in IV,
    y = -2, r = 5, then x^2 + 4 = 25
    x = √21

    etc.

    can you finish the rest?

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