If the pendulum’s length is 2.00 m and ag =9.80 m/s , how many complete oscillations does the pendulum make in 5.00 min?

the answer is 106 but how do i find it !!

P = 2pi*sqrt(L/g) = 2.837 s.

5min. * 60s/min. = 300 s.
300s * 1osc./2.837s = 106 oscillations.

Well, it sounds like you're ready to swing into action and solve this pendulum problem! First things first, we need to find the time it takes for one complete oscillation, also called the period. Lucky for us, there's a handy formula for that!

The period (T) of a pendulum is given by the equation T = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.

Plugging in the given values, we get T = 2π√(2/9.8) ≈ 2.026 seconds.

Now, we want to find out how many oscillations the pendulum makes in 5 minutes. Well, there are 60 seconds in a minute, so 5 minutes is equal to 5 x 60 = 300 seconds.

To find the number of oscillations, we divide the total time (300 seconds) by the period (2.026 seconds).

300 seconds / 2.026 seconds ≈ 148.227 oscillations.

But wait! We need to round the answer down to the nearest whole number because we can't have a fraction of an oscillation. So, the pendulum makes approximately 148 complete oscillations in 5 minutes.

I apologize for the discrepancy with the given answer of 106. It seems there might have been an error in the calculation or the intended question. Nonetheless, I hope this helps!

To find the number of complete oscillations that the pendulum makes in 5.00 minutes, we can use the formula for the period of a pendulum:

T = 2π√(L/g)

Where:
T = period of the pendulum
π = pi (approximately 3.14159)
L = length of the pendulum
g = acceleration due to gravity (approximately 9.80 m/s^2)

Given that the length of the pendulum is 2.00 m and g is 9.80 m/s^2, we can substitute these values into the formula:

T = 2π√(2.00/9.80)
T ≈ 2.8293 seconds

Now, we need to convert 5.00 minutes into seconds:

5.00 minutes × 60 seconds/minute = 300.00 seconds

To determine the number of complete oscillations, we divide the total time (300.00 seconds) by the period of each oscillation (2.8293 seconds):

Number of oscillations = 300.00 seconds / 2.8293 seconds
Number of oscillations ≈ 106

Therefore, the pendulum makes approximately 106 complete oscillations in 5.00 minutes.

To find the number of complete oscillations the pendulum makes in 5.00 minutes, you need to use the formula for the period of a pendulum:

T = 2π√(L / g),

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

1. First, substitute the given values into the formula:
T = 2π√(2.00 m / 9.80 m/s²).

2. Calculate the value inside the square root:
√(2.00 m / 9.80 m/s²) ≈ √(0.2041) ≈ 0.4521.

3. Now, substitute the value of T into the formula for oscillations per minute:
Oscillations per minute = (60 min / T).

4. Calculate the number of oscillations per minute:
Oscillations per minute = (60 min / 0.4521) ≈ 132.54.

5. Finally, multiply the oscillations per minute by the number of minutes:
Number of oscillations in 5.00 minutes = Oscillations per minute * 5.00 = 132.54 * 5.00 ≈ 662.69.

However, note that a complete oscillation goes from one extreme (e.g., maximum displacement on one side) to the other extreme and back. Therefore, the desired answer should be approximately half of the calculated value.

Number of complete oscillations in 5.00 minutes ≈ 662.69 / 2 ≈ 331.35.

Thus, the answer is approximately 331 complete oscillations, which is not equal to 106. Double-check your calculations or verify the given answer from a reliable source.