An object floats with half of its volume beneath the surface of the water. The weight of the displaced water is 2000N. What is the weight of the object?
I'm confused by this problem. How would I go about solving this? My guess would be that the weight of the object is 2000N. Is this right?
v*d*g=200*gravity
v*d=200
volume * density = mass
somass remain 200 or 2000n as said above
Yes. They are trying to confuse you with extra information.
No matter how much of the object is submerged, as long as it is floating, the weight of the object equals the weight of the displaced fluid. That is Archimides Law (or Principle).
It should be a Law by now.
Oh, I see you've been taking a dive into the world of buoyancy! Let me help you out with that.
If an object floats with half of its volume beneath the surface of the water, it means that the buoyant force acting on the object (which is equal to the weight of the displaced water) is equal to the weight of the object itself. So, in this case, the weight of the object would indeed be 2000N.
You're right on the money! Well, more like 2000N on the scale, but you get the idea. Keep up the good work!
To solve this problem, you need to consider Archimedes' principle, which states that the buoyant force exerted on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
In this case, the weight of the displaced water is given as 2000N. Since the object floats with half of its volume beneath the surface of the water, it means that the buoyant force acting on the object is equal to half its weight.
Let's assume the weight of the object is W. The buoyant force acting on the object is 0.5W (half its weight), and this force is equal to the weight of the displaced water, which is given as 2000N.
Therefore, we can set up the equation:
0.5W = 2000N
To find the weight of the object, we can solve for W by multiplying both sides of the equation by 2:
W = 2 * 2000N
W = 4000N
So, the weight of the object is 4000N, not 2000N as you initially guessed.
To solve this problem, you need to understand the concept of buoyancy and Archimedes' principle.
Archimedes' principle states that an object submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid that it displaces.
In this problem, the weight of the displaced water is given as 2000N. Since the object floats with half of its volume beneath the surface of the water, we can conclude that the buoyant force acting on the object is equal to its weight.
To find the weight of the object, you need to determine the buoyant force acting on it. The buoyant force is given by the formula:
Buoyant force = Weight of displaced fluid
Since the buoyant force is equal to the weight of the object (as it is floating), we can rewrite the equation as:
Weight of object = Weight of displaced fluid
So, in this case, the weight of the object is also 2000N. Your guess is correct!
To summarize:
The weight of the object is given as 2000N because it is the same as the weight of the water it displaces, according to Archimedes' principle.