7x + 3y = 42 graph this equation using the intercepts method graph this equation using the intercepts method

subtract 7x from both sides

3y = -7x + 42

divide both sides by 3

y = -7/3x + 14

your y-intercept is 14 and your slope is -7/3, or down 7 right 3. Assuming that is what you mean by the intercepts method.

To graph the equation 7x + 3y = 42 using the intercepts method, we need to find the x-intercept and the y-intercept.

The x-intercept is the point where the line crosses the x-axis, which occurs when y = 0. To find the x-intercept, we set y = 0 and solve for x:
7x + 3(0) = 42
7x = 42
x = 42/7
x = 6

So, the x-intercept is (6, 0).

The y-intercept is the point where the line crosses the y-axis, which occurs when x = 0. To find the y-intercept, we set x = 0 and solve for y:
7(0) + 3y = 42
3y = 42
y = 42/3
y = 14

So, the y-intercept is (0, 14).

Now, we plot the x-intercept at (6, 0) and the y-intercept at (0, 14) on a coordinate plane.

The x-intercept (6, 0) is located at 6 units to the right of the origin on the x-axis, and the y-intercept (0, 14) is located 14 units above the origin on the y-axis.

Now, draw a straight line passing through both points. This line represents the graph of the equation 7x + 3y = 42.

Here is a visual representation of the graph: