Student has a probality to pass in english is 60% , and probality to pass in english and maths is 54% , what is probality he will fail in maths
Say the probability he'll pass English is Prob(E) = 0.6. The probability he'll pass in both English and Maths is Prob(E&M) = 0.54. Provided the probability that he'll pass English is independent of the probability that he'll pass Maths (and note that's an assumption we're making that may or may not be true), then the probability that he'll pass Maths must be Prob(M) = Prob(E&M) / Prob(E) = 0.54/0.6 = 0.9, because Prob(E&M) = Prob(E) x Prob(M) if the events are independent. So Prob(M) = 0.9. But we were asked for the probability that he'll fail Maths, not pass it, and that's 1 - Prob(M). So the answer must be 1 - 0.9 = 0.1. Do you agree?
To find the probability of failing in math, we need to subtract the probability of passing both English and math from the probability of passing in English.
Let's assign the following probabilities:
P(Pass English) = 0.60
P(Pass English and Math) = 0.54
To calculate the probability of failing in math, we can use the formula:
P(Fail Math) = P(Pass English) - P(Pass English and Math)
P(Fail Math) = 0.60 - 0.54 = 0.06
Therefore, the probability the student will fail in math is 0.06 or 6%.
To find the probability of failing in math, we need to know the probability of passing in math and the probability of passing in both English and math.
Let's assume the probability of passing in math is represented by P(passing in math).
Given that the probability of passing in English is 60%, we can say P(passing in English) = 0.60.
The probability of passing in both English and math is given as 54%, so we can say P(passing in English and math) = 0.54.
Now, we can use the formula for the probability of the intersection of two independent events to find P(passing in math).
P(passing in math) = P(passing in English and math) / P(passing in English)
P(passing in math) = 0.54 / 0.60
P(passing in math) = 0.90
Therefore, the probability of failing in math is 1 - P(passing in math).
P(failing in math) = 1 - 0.90
P(failing in math) = 0.10
So, the probability that the student will fail in math is 10%.