The length of a rectangle is 3 times the width . If the perimeter is to be at least 48 meters, what are the possible values for the width? (If the perimeter is at least 48 meters, then it is greater than or equal to 48 meters.)

Enter the expression for the width as an inequality. Do not include units in your answer.

width = x

length = 3x
perimeter = 3x+3x+x+x > or = 48

8x > or = 48
divide by 8

x > or = 6

THANKS!!!!! =)

Let's call the width of the rectangle as 'w'.

According to the given information, the length of the rectangle is 3 times the width, so the length can be expressed as 3w.

The perimeter of a rectangle is given by the formula: perimeter = 2 * (length + width).

Using this formula, we can calculate the perimeter of the rectangle:
perimeter = 2 * (3w + w) = 2 * (4w) = 8w.

Since the perimeter needs to be at least 48 meters, we can write the inequality:
8w ≥ 48.

Therefore, the expression for the width as an inequality is:
w ≥ 6.

This means that the width of the rectangle needs to be greater than or equal to 6 meters in order for the perimeter to be at least 48 meters.

To find the possible values for the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is given by:

Perimeter = 2 * (length + width)

Let's denote the width as 'w', and since the length is 3 times the width, we can express the length as 3w.

Using the given information, the perimeter is at least 48 meters, so we can write the inequality:

48 ≤ 2 * (3w + w)

Simplifying the expression:

48 ≤ 2 * (4w)

48 ≤ 8w

Dividing both sides of the inequality by 8, we get:

6 ≤ w

Therefore, the width 'w' of the rectangle must be greater than or equal to 6.

So, the possible values for the width of the rectangle are w ≥ 6.