ray OC bisects <AOB, ray OD bisects <AOC, RAY OE BISECTS <AOD, RAY OF BISECTS <AOE NAD RAY OG BISECTS <FOC
IF THE MEASUREOF <BOF EQUALS 120
DEGREES, THEN WHAT IS THE MEASURE OF <DOE?
THE ANSWER WILL BE 16 DEEGRES..
BECAUSE THE ANSWERE WILL NOT BE X/2... BECAUSE IS NOT A BISECTOR OF THAT HOLE <... IS A I/3... SO IT WILL BE X/3.
the surface area of a sphere if the radius, r, is 6 meters.
Ray OC bisects <AOB, ray OD bisects <AOC, ray OE bisects <AOD, ray OF bisects <AOE and ray OG bisects <FOC ig <COG =35, then m<EOG = ?
To find the measure of <DOE, we need to use the angle bisector theorem.
The angle bisector theorem states that when a ray bisects an angle, it divides the angle into two congruent angles.
Given that ray OC bisects <AOB, we know that <AOC and <BOC are congruent.
Similarly, ray OD bisects <AOC, so <AOD and <COD are congruent.
Since ray OE bisects <AOD, <AOC is divided into two congruent angles: <DOE and <EOC.
Finally, since ray OF bisects <AOE and <AOC is divided into two congruent parts, we can conclude that <BOF is also congruent to <DOE.
Thus, if the measure of <BOF is 120 degrees, then the measure of <DOE is also 120 degrees. So, the measure of <DOE is 120 degrees.