Luisa and Connor had $360 altogether. After Connor gave Luisa 2/5 oh his money, she had the same amount of money as he did. How much money did Connor have in the beginning?

360=L+C

L+2/5 C=C-2/5C

360-C+4/5 C=C
360= 6/5 C
C= 5*360/6 =300
L=60

Let's assume that Connor had X dollars in the beginning.

After giving 2/5 of his money to Luisa, Connor has (1 - 2/5) * X = 3/5 * X dollars left.

Since Luisa has the same amount of money as Connor after receiving 2/5 of his money, Luisa has 3/5 * X dollars.

Together, they have a total of $360, so:

3/5 * X + 3/5 * X = $360

Combining like terms:

6/5 * X = $360

To solve for X, we divide both sides of the equation by 6/5:

X = $360 / 6/5

X = $360 * 5/6

X = $300

Therefore, Connor had $300 in the beginning.

To solve this problem, let's set up some equations to represent the given information:

Let's say Luisa had L dollars and Connor had C dollars in the beginning.
According to the first sentence, they had a total of $360, so we can write the equation: L + C = 360.

According to the second sentence, after Connor gave Luisa 2/5 of his money, Luisa had the same amount of money as Connor. This means that Luisa received 2/5 of Connor's money.
We know that Luisa's money after receiving Connor's money is (L + (2/5)C), and this should be equal to Connor's initial money, C.
So, we can write the equation: L + (2/5)C = C.

Now we have a system of two equations. Let's solve it to find the values of L and C.

From the first equation, we can isolate L by subtracting C from both sides:
L = 360 - C.

Substituting this value of L into the second equation, we get:
(360 - C) + (2/5)C = C.

Simplifying the equation:
360 - C + (2/5)C = C.
360 = (3/5)C.

Finally, to solve for C, we multiply both sides by (5/3):
C = 360 * (5/3) = 600.

Therefore, Connor had $600 in the beginning.

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