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The formula T=2*pi*sqrt[L/32] gives the period of a pendulum of length l feet. The period P is the number of seconds it takes for the pendulum to swing back and forth once. Suppose we want a pendulum to complete three periods in 2 seconds. How long should the pendulum be? Thank you so much for helping. The solution must be sbout 0.36 ft. I tried everything but I'm still wrong. Thanks again!!!!

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2 answers
  1. To complete three periods in 2 seconds, the period must be
    T = 2/3 = 0.6667 s

    I will use your formula although physics says that the denominator in the sqrt[L/32] should be 32.2 ft/s^2, not 32. That is the value of g, the acceleration due to gravity.

    Anyway, using 0.6667 = 2*pi*sqrt(L/32),
    sqrt(L/32) = 0.10611
    L/32 = (0.10611)^2 = 0.01127
    L = 0.3603 feet

    With the correct formula,
    L/32.2 = (0.10611)^2
    L = 0.3625 ft

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  2. Wrong the answer is 10.5 feet

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