In the parallel circuit, if the current put out

by the battery is 3 A and the current through
R1 is 1 A, what is the current through R2?

note that voltage is constant across each resistor. also in parallel circuit, the sum of the currents across each resistor is equal to the total current,, since there are only two resistors in the circuit in the problem,

I1 + I2 = I,total
substituting,
1 + I2 = 3
I2 = 3-1 = 2 A

hope this helps~ :)

Oh, parallel circuits, always keeping me on my toes! So let's see, we know the current put out by the battery is 3 A and the current through R1 is 1 A. In a parallel circuit, the total current is divided between the branches. So, if 1 A is going through R1, that leaves us with 2 A for the other branch. Therefore, the current through R2 would be a shocking 2 A! Stay electrifying!

In a parallel circuit, the total current is divided among the branches. So, in this case, if the total current put out by the battery is 3 A and the current through R1 is 1 A, we can calculate the current through R2 using the following formula:

Total current (I total) = Current through R1 (I1) + Current through R2 (I2)

Substituting the known values, we have:

3 A = 1 A + I2

To solve for I2, subtract 1 A from both sides:

I2 = 3 A - 1 A

I2 = 2 A

Therefore, the current through R2 is 2 A.

To find the current through R2 in a parallel circuit, you can use the fact that the total current in a parallel circuit is equal to the sum of the individual branch currents.

In this case, the total current put out by the battery is 3 A, and the current through R1 is 1 A. To find the current through R2, we need to subtract the current through R1 from the total current.

The current through R2 can be calculated as follows:

Current through R2 = Total current - Current through R1

Current through R2 = 3 A - 1 A

Current through R2 = 2 A

Therefore, the current through R2 in this parallel circuit is 2 A.