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The density of gold is 19.3 x 10^3 kg/m^3. What buoyant force does a .6 kg gold crown experience when it is immersed in water?

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  1. Buoyant force = (Water density) x (gold volume)x g

    The volume of the gold is
    (mass)/(gold density)= 3.11*10^-5 m^3

    The density of water is 1000 kg/m^3

    The answer will be in Newtons after multiplying by g.

    This is obviously not a tooth crown - At 0.6 kg, it would weigh 19 oz. and cost %26,000 at today's prices

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